The 100%-Norm.Dist(value,mean,sd,true) percent of the population has an iq over 115
According to the statement
we have to find that the what percent of the population has an iq over 115.
And from given information,
the mean iq score is 100 and the standard deviation is 15.
And
Normal distribution, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.
And by use of this formula, we find the percentage of the population has an iq over 115.
Then the result will comes as 100%.
hence, 100%-Norm.Dist(value,mean,sd,true)
So, The 100%-Norm.Dist(value,mean,sd,true) percent of the population has an iq over 115.
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