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4 years ago

What is the answer to my problem

Mathematics

2 answers:

ASHA 777 [7]4 years ago

6 0

Answer:

Step-by-step explanation:

faltersainse [42]4 years ago

3 0

Answer:

4 hhhajajajajajajajjansnsnnxbcbcb jnfh ncn ncnnxndndndncnnxnxnxnxnxnxnxnnxnx

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The board of directors of a corporation must select a president, a secretary, and a treasurer. In how many possible ways can thi

scoundrel [369]

Answer:

9240 ways.

Step-by-step explanation:

A president, a secretary, and a treasurer are to be selected from the board of directors of a corporation.

We have to determine among 22 members on the board of directors, in how many possible ways this can be done.

Since all the three post s are different then number ways of selecting 3 members from the list of 22 members on the board of directors will be

$^{22}P_{3} = 9240$ ways. (Answer)

3 0

3 years ago

What is -.36 in m/n forms simplify

Arte-miy333 [17]

Answer:

0.36/1 is the answer...I guess

5 0

3 years ago

3 (5) = 17? is this true?

poizon [28]

Answer:

3 (5) = 15

multiply three by 5.

It's is not true, it is false.

3 0

2 years ago

Read 2 more answers

Automobiles arrive at a vehicle equipment inspection station according to a Poisson process with rate α = 8 per hour. Suppose th

Elis [28]

Answer:

a) The probability that exactly eight arrive during the hour and all eight have no violations is 0.0005.

b) For any fixed y ≥ 8, the probability that y arrive during the hour, of which eight have no violations is:

$P(X=y\,\&\,nv=8)=\frac{4^ye^{-8}}{8!(y-8)!}$

c) The probability that eight "no-violation" cars arrive during the next hour is 0.030.

Step-by-step explanation:

a) The probability that exactly eight arrive during the hour and all eight have no violations is equal to the product of the probability of arrival of 8 vehicules and the probability of having 8 vehicules with no violations.

$P(X=8\,\&\,no\, violations)=P(no\, violations|X=8)*P(X=8)\\\\P(X=8\,\&\,nv)=(0.5)^8*\frac{8^8e^{-8}}{8!} = 0.0039*0.1396=0.0005$

b) For any fixed y ≥ 8, the probability that y arrive during the hour, of which eight have no violations is:

$P(X=y\,\&\,nv=8)=P(nv=8|X=y)*P(X=y)\\\\P(X=y\,\&\,nv=8)=[\binom{y}{8}(0.5)^8*(0.5)^{y-8}]*\frac{8^ye^{-8}}{y!} =\frac{y!}{8!(y-8)!}0.5^y *8^y*\frac{e^{-8}}{y!}\\\\ P(X=y\,\&\,nv=8)=(\frac{y!}{y!})(0.5*8)^y\frac{e^{-8}}{8!(y-8)!}=\frac{4^ye^{-8}}{8!(y-8)!}$

c) Using the result of point (b) we can express the probability that eight "no violation" vehicules arrive durting the next hour as:

$P(nv=8)=\sum\limits^\infty_{y=8} {\frac{4^ye^{-8}}{8!(y-8)!}}=\frac{e^{-8}}{8!} \sum\limits^\infty_{y=8} {\frac{4^y}{(y-8)!}}=\frac{e^{-8}4^{8}}{8!} \sum\limits^\infty_{y=8} {\frac{4^{y-8}}{(y-8)!}}\\\\P(nv=8)=\frac{e^{-8}4^{8}}{8!} \sum\limits^\infty_{z=0} {\frac{4^{z}}{z!}}=\frac{e^{-8}4^{8}}{8!}*e^4=\frac{e^{-4}4^{8}}{8!}\\\\P(nv=8)= 0.030$

5 0

3 years ago

Not have a ratio of 2:3:5.

Bad White [126]

Answer:

2to3to5

Step-by-step explanation:

4 0

3 years ago