You yourself put the answer to the question in the Question. the answer is paragraph. lol
Answer:
Data redundancy.
Explanation:
A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to create, store, modify, retrieve and manage data or informations in a database. Generally, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.
A data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.
In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.
Data redundancy is the name of situation where the same data is stored unnecessarily at different places.
Simply stated, data redundancy can be defined as a condition which typically involves storing the same data in multiple storage locations. Thus, data redundancy connotes the unnecessary repetition of the same piece of data (informations) either deliberately or for some specific reasons.
Answer:
From what I see, you're trying to convert an int to a double&. This is illegal. Do you have any arrays with ints?
Answer:
TRUE
Explanation:
Negotiation may be defined as the process or a method with the help of which people try to settle their differences or they try to come to a conclusion in a matter of differences. Here an agreement or a compromise is reached without any dispute and arguments. It is a skill.
It involves preparing for the negotiation with other person, understanding and knowing when one needs to walk out of the negotiation process to avoid arguments and working towards the common goal of achieving an agreement.
Therefore, the answer is true.
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
