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vekshin1
3 years ago
11

Which expression is equivalent to 3x + 3x + 3x? From Performance Matters

Computers and Technology
2 answers:
ZanzabumX [31]3 years ago
4 0
Answer:
The answer is 9x
mamaluj [8]3 years ago
3 0
9x because you can add 3x+3x+3x because they are the same and can be added
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Write a C program (doublecopy) that allows a user to extract some part of an existing file (fileSource) and copy it twice to a n
Slav-nsk [51]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <sys/stat.h>

#include <stdlib.h>

#include <fcntl.h>

#include <errno.h>

#include <unistd.h>

extern int errno;

struct stat st;

int main(int argc, char **argv){

  int num1 = atoi(argv[1]); // Getting num1 from user

  int num2 = atoi(argv[2]); // Getting num2 from user

  char *fileSource = argv[3];

  char *fileTarget = argv[4];

 

  int source_fd = open(fileSource, O_RDONLY); // opening the file in read only mode

  int target_fd = open(fileTarget, O_WRONLY | O_CREAT); // opening the target file in Writeonly mode if file is not found it will create

   

  char *ch = (char *) calloc(num2+num1, sizeof(char));

 

  stat(fileSource, &st);

  if(st.st_size < (num1 + num2)){

      printf("File Size is smaller than the specified bytes\n");

      read(source_fd, ch, st.st_size); // reading the file upto the end

      write(target_fd, ch, st.st_size); // write to the file

      write(target_fd, ch, st.st_size); // two times writing to the file

  }else{

      if(lseek(source_fd, (off_t)num1, SEEK_SET) < 0 ) // moving the cursor to after the specified bytes from the start

      {

          printf("Some Error occured while seeking the file");

          return -1;

      }

      read(source_fd, ch, num2); // reading num2 bytes from the source

      write(target_fd, ch, num2); // writing two times to the target

      write(target_fd, ch, num2);

     

  }

 

  return 0;

 

}

1 2 #include <stdio.h> #include <sys/stat.h> #include <stdlib.h> #include <fcntl.h> #include <errno.h> #include <unistd.h> 4

The code screenshot and code output are attached below.

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