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vekshin1
3 years ago
11

Which expression is equivalent to 3x + 3x + 3x? From Performance Matters

Computers and Technology
2 answers:
ZanzabumX [31]3 years ago
4 0
Answer:
The answer is 9x
mamaluj [8]3 years ago
3 0
9x because you can add 3x+3x+3x because they are the same and can be added
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Which line of code in this program is MOST likely to result in an error
rjkz [21]

Answer:

What are the choices?

Explanation:

7 0
3 years ago
Read 2 more answers
Can you structure this code in if-statements?
Naddika [18.5K]
Not sure what quizScore1-5 is, but here it is. Also, I'm not entirely sure what language you're working with here, but null can't be returned as an integer. If it were a string, for example, it'd be possible as string is an object reference type.

public int getData(int dataNumber)
{
    if (dataNumber == 1)
        return quizScore1;
    else if (dataNumber == 2)
        return quizScore2;
    else if (dataNumber == 3)
        return quizScore3;
    else if (dataNumber == 4)
        return quizScore4;
    else if (dataNumber == 5)
        return quizScore5;
    else
        return 0;
}
3 0
3 years ago
g Write a function called price_of_rocks. It has no parameters. In a while loop, get a rock type and a weight from the user. Kee
Scilla [17]

Answer:

<u>The pseudocode:</u>

FUNCTION price_of_rocks():

  SET total = 0

  while True:

      INPUT rock_type

      INPUT weight

      if rock_type is "Quartz crystals":

         SET total += weight * 23

      elif rock_type is "Garnets":

         SET total += weight * 160

      elif rock_type is "Meteorite":

         SET total += weight * 15.50

       

       INPUT choice

       if choice is "n":

           break

 

   RETURN total

END FUNCTION

<u>The code:</u>

def price_of_rocks():

   total = 0

   while True:

       rock_type = input("Enter rock type: ")

       weight = float(input("Enter weight: "))

       

       if rock_type == "Quartz crystals":

           total += weight * 23

       elif rock_type == "Garnets":

           total += weight * 160

       elif rock_type == "Meteorite":

           total += weight * 15.50

           

       choice = input("Continue? (y/n) ")

       if choice == "n":

           break

   

   return total

print(price_of_rocks())

Explanation:

Create a function named price_of_rocks that does not take any parameters

Initialize the total as 0

Create an indefinite while loop. Inside the loop:

Ask the user to enter the rock_type and weight

Check the rock_type. If it is "Quartz crystals", multiply weight by 23 and add it to the total (cumulative sum). If it is "Garnets", multiply weight by 160 and add it to the total (cumulative sum). If it is "Meteorite", multiply weight by 15.50 and add it to the total (cumulative sum).

Then, ask the user to continue or not. If s/he enters "n", stop the loop.

At the end of function return the total

In the main, call the price_of_rocks and print

4 0
3 years ago
Anyone from qls<br><br>or grax here<br><br>in bs​
PIT_PIT [208]

Answer:

No, I don't think I've ever heard of DLS or Grax either if I'm being honest.

May I have brainliest please? :)

7 0
3 years ago
Modern ancestor of the typewriter
Rashid [163]
I would think Microsoft Word would be the answer. It does everything a typewriter can.
4 0
3 years ago
Read 2 more answers
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