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vekshin1
3 years ago
11

Which expression is equivalent to 3x + 3x + 3x? From Performance Matters

Computers and Technology
2 answers:
ZanzabumX [31]3 years ago
4 0
Answer:
The answer is 9x
mamaluj [8]3 years ago
3 0
9x because you can add 3x+3x+3x because they are the same and can be added
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Which tools is used to bundle cables neatly inside and outside of a computer?​
Ugo [173]

Answer:

Cable Ties

Explanation:

6 0
3 years ago
How did technology change the world
Crank

Answer:

Technology has changed the world for the better.

Explanation:

Without technology, many of the things we take for advantage, such as, credit cards, calling people from far distances, heck even being able to call to across the world from where you are right now. Technology has revolutionized many things we use commonly on a day-to-day basis.

3 0
2 years ago
Read 2 more answers
Modify the code below to do the following:
Kitty [74]

Answer:

The code is appropriately given below with comments for better understanding

Explanation:

#include <linux/init.h>

#include <linux/module.h>

#include <linux/kernel.h>

#include <linux/hash.h>

#include <linux/gcd.h>

#include <asm/param.h>

#include <linux/jiffies.h>

/* This function is called when the module is loaded. */

static int simple_init(void)

{

  printk(KERN_INFO "Loading Module\n");

  printk(KERN_INFO "These are the HZ: %d\n", HZ);

  printk(KERN_INFO "These are the jiffies: %lu\n", jiffies);

  printk(KERN_INFO "Golden Ratio is: %lu\n", GOLDEN_RATIO_PRIME);  

  return 0;

}

/* This function is called when the module is removed. */

static void simple_exit(void) {

  printk(KERN_INFO "Removing Module");

  unsigned long a = gcd(3300, 24);

  printk(KERN_INFO "Greatest Common Denominator between 3,300 and 24 is: %lu\n", a);

  printk(KERN_INFO "These are the jiffies: %lu\n", jiffies);

}

/* Macros for registering module entry and exit points. */

module_init( simple_init );

module_exit( simple_exit );

MODULE_LICENSE("GPL");

MODULE_DESCRIPTION("Simple Module");

MODULE_AUTHOR("SGG");

7 0
3 years ago
A perfect binary tree is a complete binary tree with all levels fully filled. Add a method in the BST class to return true if th
algol [13]

Answer:

class BST {

static class Node

{

int val;

Node left, right;

}

static boolean checkPerfectBT(Node node, int h, int d)

{

if (node == null)

return true;

 

if (node.left == null && node.right == null)

{

if(h==d+1)

return true;

else

return false;

}

 

if (node.left == null || node.right== null)

return false;

 

return checkPerfectBT(node.left, h, d+1) && checkPerfectBT(node.right, h, d+1);

}

static int height(Node node)

{

int dep = 0;

while (node != null)

{

node = node.right;

dep=dep+1;

}

return dep;

}

static boolean isPerfectBT(Node node)

{

int h = height(node);

return checkPerfectBT(node, h, 0);

}

 

static Node addNode(int x)

{

Node node = new Node();

node.val= x;

node.right = null;

node.left = null;

return node;

}

public static void main(String args[])

{

int i,j,k;

Node node= null;

node = addNode(34);

node.left = addNode(2);

node.right = addNode(322);

 

node.left.left = addNode(21);

node.left.right = addNode(23);

node.right.left = addNode(37);

node.right.right = addNode(54);

 

if (isPerfectBT(node) == true)

System.out.println("This is a Perfect Binary tree");

else

System.out.println("This is Not a perfect Binary Tree");

}

}

Explanation:

  • Calculate the depth of BST by using a while loop until it reaches a null value.
  • In the addNode method, make an object of Node class.
  • In the main method, pass the values to addNode method.
  • Finally display the relevant message to show if it's Perfect or not.
6 0
3 years ago
In this assignment, you will develop a C++ program and a flowchart that calculates a cost to replace all tablets and desktop com
Alexeev081 [22]

Answer:

Explanation:

The objective of this program we are to develop is to compute a C++ program and a flowchart that calculates a cost to replace all tablets and desktop computers in a business.

C++ Program

#include<iostream>

#include<iomanip>

using namespace std;

/*

⦁ // Name:

⦁ // Date:

⦁ // Program Name:

⦁ // Description:

*/

int main()

{

const double SalesTaxRate = .075, DiscountPercent = .10, FinanceCharge = .15;

const double TABLET = 320.00, DESKTOP = 800.00;

double total = 0.0, subTotal = 0.0,avg=0.0;

int numberOfTablets, numberOfDesktop;

cout << "-------------- Welcome to Computer Selling Company ------------------ ";

cout << "Enter number of tablets: ";

cin >> numberOfTablets;

cout << "Enter number of desktops: ";

cin >> numberOfDesktop;

subTotal = TABLET * numberOfTablets + numberOfDesktop * DESKTOP;

char choice;

cout << "Paying cash or financing: (c/f): ";

cin >> choice;

cout << fixed << setprecision(2);

if (choice == 'c' || choice == 'C')

{

cout << "You have choosen paying cash." << endl;

total = subTotal - subTotal * DiscountPercent;

cout << "Discount you get $" << subTotal * DiscountPercent<<endl;

cout << "Sales Tax: $" << SalesTaxRate * total << endl;

total = total + total * SalesTaxRate;

cout << "Total computers' Cost: $" << total << endl;

avg = total / (numberOfDesktop + numberOfTablets);

cout << "Average computer cost: $ " << avg << endl;

}

else if (choice == 'f' || choice == 'F')

{

cout << "You have choosen Finance option." << endl;

total = subTotal + subTotal * FinanceCharge;

cout << "Finance Charge $" << subTotal * FinanceCharge << endl;

cout << "Sales Tax: $" << SalesTaxRate * total << endl;

total = total + total * SalesTaxRate;

cout << "Total computers' Cost: $" << total << endl;

avg = total / (numberOfDesktop + numberOfTablets);

cout << "Average computer cost: $ " << avg << endl;

}

else

{

cout << "Wrong choice.......Existing.... ";

system("pause");

}

//to hold the output screen

system("pause");

} }

OUTPUT:

The Output of the program is shown in the first data file attached below:

FLOWCHART:

See the second diagram attached for the designed flowchart.

5 0
3 years ago
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