Free space going around the town states
<span>The schema will have to accommodate to make the person more easily able to perform the new task. Accommodation allows the new information to be made a part of a schema without changing the overall concepts in the schema. The schema itself stays unchanged for the most part, but the new information is more of a "tweak" to the schema than a full-on update.</span>
Answer:
#include <stdio.h>
int fib(int n) {
if (n <= 0) {
return 0;
}
if (n <= 2) {
return 1;
}
return fib(n-1) + fib(n-2);
}
int main(void) {
for(int nr=0; nr<=20; nr++)
printf("Fibonacci %d is %d\n", nr, fib(nr) );
return 0;
}
Explanation:
The code is a literal translation of the definition using a recursive function.
The recursive function is not per se a very efficient one.
The answer is commissioned
Nested
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