Answer:
Well the real question would be how comfortable are you with computer software if not good or none at all I feel the answer would simply be buy the game in the Nintendo store or you could buy the key for the Nintendo store for much cheaper on 3rd party websites give that a try hope this helped you. :)
Answer:
How did technology affect the growth of cities and housing within them? ... Advances in technology and greater business efficiency and productivity further expanded the variety of goods and services within their reach. The growing middle class also supported an expansion of higher education.
Explanation:
Answer:
c = 1 # global variable
jhjl jh
def add():
c = 1 # global variable
def add():
print(c)
add()
c = c + 2 # increment c by 2
print(c)
add()
Explanation:
Answer:
Filtering procedure provides an essay and convenient way to visualize or work only with the data we desire without needing to delete those we do not need at that moment.
Filter allows you to view only the information you want to see. Only the required information is displayed at that moment once the filter criteria has been checked.
Filter temporarily hides rows of data that you do not need to view. Rows of data which aren't needed at the moment are temporarily hidden in other to allow user concentrate on the needed data.
Filter allows you to filter text and numeric data. Filtering allows for different filtering criteria, if the user requires working or viewing only on text or numeric data, it is possible with spreadsheet filter.
Explanation:
Filter allows you to view only the information you want to see.
Filter temporarily hides rows of data that you do not need to view
Filter allows you to filter text and numeric data.
Answer:
class studentType: public personType
{
public:
virtual void print() = 0;
virtual void calculateGPA() = 0;
void setID(long id) {
studentId = id;
}
void setCourses(const string c[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
courses[i] = c[i];
}
}
void setGrades(const char cG[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
coursesGrade[i] = cG[i];
}
}
long getID() {
return studentId;
}
string* getCourses() {
return courses;
}
char* getGrades() {
return coursesGrade;
}
studentType(string fName = "", string lastName = "",
long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);
private:
long studentId;
string courses[6];
char coursesGrade[6];
int noOfCourses;
};
Explanation:
Code rewritten
