Answer:
- Hannah: 2.11 is a terminating decimal that can be written as 2 11/100. Rational numbers can be expressed as fractions.
Step-by-step explanation:
<u>The answer choices are:</u>
- <u>Gus</u>: 2.11 repeats because there are two 1s.
- <u>Gus</u>: 2.11 is a repeating decimal because it stops.
- <u>Hannah</u>: 2.11 is a rational number because it's a decimal.
- <u>Hannah</u>: 2.11 is a terminating decimal that can be written as 2 11/100. Rational numbers can be expressed as fractions.
<u>The correct one is:</u>
- Hannah: 2.11 is a terminating decimal that can be written as 2 11/100. Rational numbers can be expressed as fractions.
The answer to the above equation is 3
Step-by-step explanation:
(a-b)³+(b-c)³+(c-a)³: (a-b)(b-c)(c-a)
Let us consider (a−b)= x, (b−c)= y and (c−a)= z.
Hence, It is obvious that:
x+y+z =0 ∵all the terms gets cancelled out
⇒We must remember the algebraic formula
x³+y³+z³−3xyz= (x+y+z) (x²+y²+z²-xy-xz-yz)
Since x+y+z=0 ⇒Whole “(x+y+z) (x²+y²+z²-xy-xz-yz)
” term becomes 0
x³+y³+z³−3xyz =0
Alternatively, x³+y³+z³= 3xyz
Now putting the value of x, y, z in the original equation
(a-b)³+(b-c)³+(c-a)³ can be written as 3(a-b)(b-c)(c-a) since (a−b)= x, (b−c)= y and (c−a)= z.
3(a-b)(b-c)(c-a): (a-b)(b-c)(c-a)
= 3 ∵Common factor (a-b)(b-c)(c-a) gets cancelled out
Answer to the above question is 3
Answer:
Step-by-step explanation:
Answer:
$1,100
Step-by-step Explanation:
Dee Wallace's salary in 2006 = $61,000 Dee Wallace's salary in 2009 = $64,300
The salary increased in => 2009 - 2006 = 3yrs
The amount of salary increased = 64,300-61000 = $3,300
The annual change of salary = 3,300/3 = $1,100
