Answer:
A sample size of 385 is needed.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.96.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
You feel that a reasonable estimate of the standard deviation is 10.0 hours.
This means that 
What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?
A sample size of n is needed. n is found when M = 1. So
Rounding up:
A sample size of 385 is needed.
Answer:
Step-by-step explanation:
We will use the standard formula for half-life:
Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.
So, we will substitute 1/2 for a and 24.3 for d. This yields:
We have a 3 gram sample. Therefore, our initial amount A₀ is 3:
And we want to find the remaining sample after 10 days. So, t=10. Substitute:
Use a calculator. So:
Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.
The answer would be A. -$16.25. It's negative because that's what Paul owes his dad. You add 10.75 and 5.50 and just turn it negative.
Answer:
Yes it does
Step-by-step explanation:
did it on edge
Answer:
i try my best to do if i can
Step-by-step explanation:
