6. If the volume of a ball is 13 cm^3, and the mass of the ball is 70 grams, what is the approximate density of the ball?

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat

djverab [1.8K]

Answer:

The function f(x) = 9,000(0.95)^x represents the situation.
After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
The range values, in the context of the situation, are limited to whole number

Step-by-step explanation:

The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.

Using x=2, we find the population in 2 years is expected to be about ...

f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120

Using x=4, we find the population in 4 years is expected to be about ...

f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330

Since population is whole numbers of bees, the range of the function is limited to whole numbers.

The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.

The choices listed above are applicable to the situation described.

7 0

3 years ago

6 x + = 0 what is x??

lapo4ka [179]

Answer:

Here are some answers

1. If you meant 6x = 0 then your answer is 0

2. If you meant 6 + x = 0 then your answer is -6

4 0

2 years ago

g Recall the example about community college students and gender. Statistics students surveyed 135 students at Tallahassee Commu

bixtya [17]

Answer:

They can either decrease the confidence level or increase the sample size, that is, survey more students.

Step-by-step explanation:

The width of a confidence interval is given by:

$M = z*\frac{\sigma}{\sqrt{n}}$

In which z is the critical value correponding to the confidence level(higher confidence level, higher z is), $\sigma$ is the standard deviation of the population and n is the size of the sample.

The students realize that this interval contains a large margin of error. What can they do to make a narrower interval?

Looking at the formula for M, they can either decrease the confidence level or increase the sample size, that is, survey more students.

4 0

3 years ago

Pls help I’ll give you brainly

sweet-ann [11.9K]

The answer to this is negative

7 0

3 years ago