6. If the volume of a ball is 13 cm^3, and the mass of the ball is 70 grams, what is the approximate density of the ball?

Mathematics

1 answer:

ASHA 777 [7]3 years ago

4 0

Answer:

<em>D. 5.385 grams per cm^2</em>

Step-by-step explanation:

Density can be found using the equation:

p = m/v

(p: density, m: mass, v: volume)

Plug in the information we know.

m = 70

v = 13

p = 70 / 13

p = density = 5.385

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he two-way table shows the medal count for the top-performing countries in the 2012 Summer Olympics. A 5-column table has 5 rows

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Answer:

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The results are attributed to the IOC country code as currently displayed by the IOC database. Usually, a single code corresponds to a single National Olympic Committee (NOC). When different codes are displayed for different years, medal counts are combined in the case of a simple change of IOC code (such as from HOL to NED for the Netherlands) or simple change of country name (such as from Ceylon to Sri Lanka). As the medals are attributed to each NOC, not all totals include medals won by athletes from that country for another NOC, such as before independence of that country. Names in italic are national entities that no longer exist. The totals of NOCs are not combined with those of their predecessors and successors.

Step-by-step explanation:

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3 years ago

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Tcecarenko [31]

The domain of the function is possible values of independant varaible such that function is defined or have real values.

So the expression

$\frac{(x+2)(x-3)}{(x-1)(x+6)}$

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So answer is,

$\frac{(x+2)(x-3)}{(x-1)(x+6)}$

Option B is correct.

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1 year ago

3. Use the following table to answer questions (a – c).

sineoko [7]

Answer:

See below

Step-by-step explanation:

B) The correlation coefficient is $r=0.75$ , which can be determined by plugging the data into a TI-84 calculator.

C) A correlation coefficient of $r=0.75$ indicates that the correlation between the independent and dependent variable (x and y in this case) is moderately strong with a positive correlation. The closer $r$ is to 1, the stronger the positive correlation. The closer $r$ is to -1, the stronger the negative correlation. If $r$ is closer to 0, then there's no correlation.