Ask question

Ask question

All categories

3 years ago

15

Mike has 876 toys building piece to share among 2 friends he wants each person to have an equal number of pieces how many pieces

does each press on get

1 answer:

max2010maxim [7]3 years ago

7 0

Answer:

if it was for mike and them 292 but if it was just those two then 438

Step-by-step explanation:

You might be interested in

Devon took a total of 4pages of notes during 2 hours of class at this rate how many hours will devon have to spend in class befo

AfilCa [17]

Answer:

7

Step-by-step explanation:

6 0

3 years ago

How do I solve this ?

Rufina [12.5K]

The answer is in the picture.

5 0

3 years ago

ASAP PLEASE HELP ILL MARK AS BRAINLIEST IN TALKING FAST

pav-90 [236]

Answer:

4 , 24 , 144 , 864 , 5184

This is a sequence which is multiplied by 6 with the new digit.

First: 4

second: 4 * 6 = 24

third: 24 * 6 = 144

fourth: 144 * 6 = 864

fifth: 864* 6 = 5184

sixth: 5184 * 6 = 31104

seventh: 31104 * 6 = 186624

This sequence is never ending. Write the first 5 five in sequence that's the answer.

5 0

2 years ago

The dimensions of a right rectangular prism are 1.5 cm, 0.5 cm and 2.25 cm.

Mnenie [13.5K]

Answer:

3 dimensions

Step-by-step explanation:

5 0

3 years ago

What is wrong with the following equation?x2+xâˆ’20/xâˆ’4=x+5a. (xâˆ’4)(xâˆ’5)â‰ x2+xâˆ’20b. The left-hand side is not defined f

joja [24]

Answer:

The answer to this question can be defined as follows:

In part (i), the answer is "option d".

In part (ii), the answer is "option 2".

Step-by-step explanation:

Given:

Part (a)

$\Rightarrow \bold{\frac{x^2+x-20}{x-4}=x+5}\\\\$

Solve the above equation:

$\Rightarrow x^2+x-20=(x+5)(x-4)\\\\\Rightarrow x^2+x-20=(x^2-4x+5x-20)\\\\\Rightarrow x^2+x-20=x^2-4x+5x-20\\\\\Rightarrow \boxed{x^2+x-20=x^2+x-20}\\$

Given:

Part (b)

$\Rightarrow \bold{ \lim_{x \to \3} \frac{x^2+x-12}{x-3}= \lim_{x \to 3} (x+4)}\\\\$

Solve the above equation:

factor of $\Rightarrow x^2+x-20 =(x-3)(x+4)$

$\Rightarrow \lim_{x \to \3} \frac{(x-3)(x+4)}{x-3}= \lim_{x \to 3} (x+4)\\\\\Rightarrow \lim_{x \to \3} (x+4)= \lim_{x \to 3} (x+4)\\\\$

apply limit value:

$\Rightarrow (3+4)= (3+4)\\\\\Rightarrow 7= 7$

6 0

4 years ago