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OlgaM077 [116]
3 years ago
9

What is the value of the underlined digits? 588_7, 6.409_7, 8.41_3, _0,184,843

Mathematics
2 answers:
Georgia [21]3 years ago
8 0
First one: ten
second one: millionth place
third one: thousandth place
fourth one: million
irga5000 [103]3 years ago
3 0
The first on is the tenth place
the second one is  the tenth place
the third one is the tenth place
the last one is the millionth place
 
hope i helped :) i might be wrong though


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Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several
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B) The 4 lb peanuts and the 1 lb mixture because the 4lb added to the 1lb of mixture give the correct percentages.

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A red gumball is 2 5/8 Inches across. A green gumball is 2 5/6 inches across and a blue gumball in 2 7/9 inches across. list the
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Because you go by which is closer to the denominator

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The area of a triangle is 18 square feet. If the base is 3 feet, what is the height of the triangle? no pic
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What is the slope of the line that passes through the points (-2, -1) and (2, -3)?
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m=\frac{-1}{2}

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3 0
3 years ago
All bags entering a research facility are screened. The screening process is not perfect so that 77% of the bags that contain fo
garik1379 [7]

Answer:

(1) 0.5933

(2) 0.8955

Step-by-step explanation:

We are given that all bags entering a research facility are screened.

Let Probability that bags entering the building contains forbidden material,

 P(F) = 0.69

Probability that bags entering the building does not contains forbidden material,   P(NF) = 1 - 0.69 = 0.31

Let event A = alarm gets triggered

Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77

Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20

(1) Probability that a bag triggers the alarm, P(A) ;

         P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)

                 = (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062

                 = 0.5933

Therefore, probability that a bag triggers the alarm is 0.5933 .

(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;

Using Bayes' Theorem;

    P(F/A) = \frac{P(F) * P(A/F)}{P(F) * P(A/F) + P(NF) *P(A/NF)} = \frac{0.69*0.77}{0.69*0.77+0.31*0.20} = \frac{0.5313}{0.5933}

               = 0.8955

6 0
3 years ago
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