Identify the form of the quadratic function:<br> f(x) = (x

Which is the decimal expansion of StartFraction 7 Over 22 EndFraction? ModifyingAbove 0. 318 with bar 0. 3ModifyingAbove 18 with

Lena [83]

The answer to the question will be 0. 3 Modifying Above 18 with bar

<h3>What will be the decimal expansion of 7 over 22? </h3>

When we divide 7 by 22 we will get 0.3181818..........

Here 3 is not repeating but 18 is repeating again and again

So it is a Non-terminating repeating number

Thus the answers to the question will be 0. 3 Modifying Above 18 with bar

To know more about Non terminating repeating numbers follow

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8 0

2 years ago

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

<em>Data given and notation </em>

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest) <em> </em>

<em>Concepts and formulas to use </em>

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

<em>Calculate the statistic</em>

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

<em>Statistical decision </em>

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

6 0

3 years ago

An exponential function with base greater than 1 eventually shows rapid growth. True or false

Stella [2.4K]

True, it keeps getting multiplied by itself more and more

7 0

2 years ago

Nine fewer than half a number is 5 more than four times the number define a varuble

Amanda [17]

5/2x-9+4x

the variable is x

4 0

3 years ago

A store offers discounts on lunch-size chip bags when buying larger quantities. The graph below represents the total cos

Ivenika [448]

The difference in the price per bag for 150 bags versus 50 bags is $0.05 per bag

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

From the diagram:

Price for 150 bag = $38

Cost per bag = $40 / 150 = $0.25

Also:

Price for 50 bag = $15

Cost per bag = $15 / 50 = $0.30

Difference in price = $0.30 - $0.25 = $0.05

The difference in the price per bag for 150 bags versus 50 bags is $0.05 per bag

Find out more on equation at: brainly.com/question/2972832

6 0

2 years ago

Identify the form of the quadratic function: f(x) = (x - 3)(X + 8)