6.665 grams of the 13 grams remain after 8 hours.
<h3>How much of a 13 gram sample of iron-52 would remain after 8 hours?</h3>
The decay equation for the 13 grams of iron-52 is:
Where N is the amount of iron-52, and t is the time in years.
Where we used the fact that the half-life is exactly 8.3 hours.
Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:
So 6.665 grams of the 13 grams remain after 8 hours.
If you want to learn more about half-life:
brainly.com/question/11152793
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Answer:
sin a = 7/25
cos a = 24/25
tan a = 7/24
Step-by-step explanation:
Trig. How wonderful. I get tripped up on these types of problems some times, so I decided to try to help! To start, write out the three ratios.
SOH (sine=opposite/hypotenuse) CAH (cosine=adjacent/hypotenuse) TOA (tangent=opposite/adjacent)
Then, label the triangle with “hypotenuse” “adjacent” and “opposite.” This helps us correctly use and find the raitos. Then, use these ratios to find out the ratios of A!
sin a = 7/25
cos a = 24/25
tan a = 7/24
If needed, just divide the ratios to get their decimal form!
Direct Variation equation: y=kx, k=y/x
42/14=3
k=3
y=3x
y=3(90)
y=270
Answer: 21 1/8 kilogram
Step-by-step explanation:
From the question, we are informed that Chef bought 3 3/4 kilograms of apples 7 1/4 kilograms of pears and 10 1/8 kilograms of oranges. The total kilogram of fruits bought would be:
= 3 3/4 + 7 1/4 + 10 1/8
Note that the Lowest Common Multiple is 8.
= 3 6/8 + 7 2/8 + 10 1/8
= 20 9/8
= 21 1/8 kilogram
