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Rashid [163]
3 years ago
15

Eliminate the parameter. x = t - 3, y = t2 + 5

Mathematics
1 answer:
Sergio [31]3 years ago
7 0

Answer:

y = x^2 +6x+14

Step-by-step explanation:

x = t - 3, y = t^2 + 5

x=t-3

Add 3 to each side

x+3 = t-3+3

x+3 =t

Substitute into the second equation

y = t^2 +5

y = (x+3)^2 +5

Foil the first term

y = (x+3) (x+3) +5

y = (x^2 +3x+3x+9) +5

y = x^2 +6x+9) +5

y = x^2 +6x+14

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