Question

Eliminate the parameter. x = t - 3, y = t2 + 5

Answer 1

Answer:

y = x^2 +6x+14

Step-by-step explanation:

x = t - 3, y = t^2 + 5

x=t-3

Add 3 to each side

x+3 = t-3+3

x+3 =t

Substitute into the second equation

y = t^2 +5

y = (x+3)^2 +5

Foil the first term

y = (x+3) (x+3) +5

y = (x^2 +3x+3x+9) +5

y = x^2 +6x+9) +5

y = x^2 +6x+14