Answer:
5.25
Step-by-step explanation:
Given that,
On Wednesday, a farmer picked 1 16/31 baskets of peppers. On Thursday, the farmer picked 2 10/21 baskets. On Friday, the farmer picked 1 5/19 baskets.
To find,
How many baskets of peppers did the farmer pick.
Solution,
It can be calculated by adding all the baskets of peppers on Wednesday, Thursday and Friday as follows :
![P=1\dfrac{16}{31}+2\dfrac{10}{21}+1\dfrac{5}{19}\\\\=\dfrac{47}{31}+\dfrac{52}{21}+\dfrac{24}{19}\\\\=5.25](https://tex.z-dn.net/?f=P%3D1%5Cdfrac%7B16%7D%7B31%7D%2B2%5Cdfrac%7B10%7D%7B21%7D%2B1%5Cdfrac%7B5%7D%7B19%7D%5C%5C%5C%5C%3D%5Cdfrac%7B47%7D%7B31%7D%2B%5Cdfrac%7B52%7D%7B21%7D%2B%5Cdfrac%7B24%7D%7B19%7D%5C%5C%5C%5C%3D5.25)
So, he will pick 5.25 baskets of peppers.
Answer:
0.61 or 8.79
Step-by-step explanation:
h = 47t − 5t²
27 = 47t − 5t²
5t² − 47t + 27 = 0
Quadratic formula:
t = [ -b ± √(b² − 4ac) ] / 2a
t = [ -(-47) ± √((-47)² − 4(5)(27)) ] / 2(5)
t = (47 ± √1669) / 10
t ≈ 0.61 or 8.79
Answer:
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Step-by-step explanation: