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vitfil [10]
3 years ago
15

The average temperature at the South Pole is - 47° F. The average temperature on the Equator is 86° F. How much warmer is the

Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

133° F

Step-by-step explanation:

So from -47 to 0 is 47. Add that on to 86.

That comes out to 133

Hope this helps

Brainliest would be appreciated

Taya2010 [7]3 years ago
4 0

Answer:

133

Step-by-step explanation:

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Help please I need help​
AlladinOne [14]

Answer: 56

Step-by-step explanation:

Add 5+5+5+11+7+16+7 to get 56

8 0
3 years ago
Write an equation for the line that passes through the points (4, 8) and (6, 2).
dybincka [34]

Answer:

y

Step-by-step explanation:

Just use the formula...,

; y - y(coordinate) = slope × [ x - x(coordinate)]

; where we firstly have to calculate the slope...,

; (8 - 2)/(4 - 6) = -3

Then substitute into the formula using point(4, 8)...and you can also use the other point if you wish to

; y - 8 = (-3)(x - 4)

; y - 8 = -3x + 12

Hence the equation of the line....,

; y = -3x + 20

3 0
4 years ago
What would the equation be for a quadratic equation with a vertex of (-5,-2)?
natta225 [31]
The quadratic equation could be: y=(x+5)^2-2
4 0
4 years ago
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Maru [420]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
What 3 relationships are truth in the construction below?? (Only if you know please though! I numbered them for you as well!)
Ahat [919]

Answer:

The 3 truth relationships are:

Line CD is the perpendicular bisector of AB ⇒ (1)

Line AB is perpendicular to the line CD ⇒ (3)

Line segment AE is congruent to line segment BE ⇒ (4)

Step-by-step explanation:

<em>When two circles </em><em>pass through the centers of each other</em><em>, then the line </em><em>joining their intersection points</em><em> is the </em><em>axis of symmetry (perpendicular bisector) </em><em>of the </em><em>segment joining their centers</em>

In the given figure

∵ Circle A passes through the center of circle B

∵ Circle B passes through the center of circle A

∴ AB is the line center

∵ Circles A and B intersected at points C and D

∴ CD is the line joining their intersection points

→ By using the rule above

∴ CD is the perpendicular bisector of AB

∴ Line CD is the perpendicular bisector of AB ⇒ (1)

∵ CD ⊥ AB

→ That means AB is perpendicular to CD

∴ Line segment AB is perpendicular to line CD ⇒ (3)

∵ CD is the perpendicular bisector of AB

∴ E is the mid-point of AB

→ That means E divides AB into two equal parts AE and BE

∴ AE = BE

∴ Line segment AE is congruent to line segment BE ⇒ (4)

5 0
3 years ago
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