The area of the given figure is equal to the area of a rectangle with sides 5 feets by 6 feets less the area of four square cut-outs of side 1 feet.
Area of the rectangle = 5 x 6 = 30 square feets.
Area of the four square cut-outs = 4(1 x 1) = 4 x 1 = 4 square feet
Area of the given figure = 30 - 4 = 26 square feet.

Area of a triangle = 1/2 x base x height
i.e. 1/2 bh = 26
bh = 26 x 2 = 52
possible values of base and height = (1 and 52), (2 and 26), (4 and 13)

5 0

2 years ago

Task: Bobby needs to buy 24 yards of

Vanyuwa [196]

Answer:

$144.00

Step-by-step explanation:

1 yard = 3 foot

24 yards = 72 foot

$2.00 per 1 foot

2×72

5 0

2 years ago

We want to factor the following expression:

S_A_V [24]

Answer:

A. (U+V)^2 or (U-V)^2

Step-by-step explanation:

$9x^6 + 6x^3y + y^2 \\ \\ = {(3 {x}^{3} )}^{2} + 2.(3x^3).y +( y)^2 \\ \\ = \bigg({3 {x}^{3} } + y \bigg)^{2} \\ \\ = \bigg({3 {x}^{3} } + y \bigg) \bigg({3 {x}^{3} } + y \bigg) \\ \\ \\ \\$

4 0

2 years ago

1. Determine a rule that could be used to explain how the volume of a

Eva8 [605]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- We will use the basic formulas for calculating the volumes of two solid bodies.

- The volume of a cylinder ( V_l ) is represented by:

$V_c = \pi *r^2*h$

- Similarly, the volume of cone ( V_c ) is represented by:

$V_c = \frac{1}{3}*\pi *r^2 * h$

Where,

r : The radius of cylinder / radius of circular base of the cone

h : The height of the cylinder / cone

- We will investigate the correlation between the volume of each of the two bodies wit the radius ( r ). We will assume that the height of cylinder/cone as a constant.

- We will represent a proportionality of Volume ( V ) with respect to ( r ):

$V = C*r^2$

Where,

C: The constant of proportionality

- Hence the proportional relation is expressed as:

V∝ r^2

- The volume ( V ) is proportional to the square of the radius. Now we will see the effect of multiplying the radius ( r ) with a positive number ( a ) on the volume of either of the two bodies:

$V = C*(a*r)^2\\\\V = C*a^2*r^2$

- Hence, we see a general rule frm above relation that multiplying the result by square of the multiple ( a^2 ) will give us the equivalent result as multiplying a multiple ( a ) with radius ( r ).

- Hence, the relations for each of the two bodies becomes:

$V = (\frac{1}{3} \pi *r^2*h)*a^2$

$V = ( \pi *r^2*h)*a^2$

8 0

2 years ago

What is the value of 0²?​

What is the value of 0²?