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abruzzese [7]
3 years ago
6

Green field country is planning to conduct a cricket match between two teams A and B. a large crowd is expected in the stadium a

s 10000 tickets have already been sold. To fulfill the viewer's requirements, the match administrators are willing to install large display screens inside the stadium
Which should display the match Live through several cameras installed on different angles in the stadium.
After carefully reading and analyzing the given scenario, you are required to suggest the most suitable serial transmission mode with two strong reasons.
Computers and Technology
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

For this requirement, we first need the Network Interface Card which supports the serial transmission, and two such can be RS-485 and EIA RS-422A. And you need to remember that parallel transmission is speedier than serial, however, they are more prone to the noise. And in both of the above cases, we can have multiple receivers and one transmitter and all that over a single line. And this line can be as long as 6000 feet and the speed can be as high as 10 MBPS, which is quite awesome and certainly apt for the above requirement.

Explanation:

Please check the answer.

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Which is better? iPhone 11 Pro Max or Samsung Galaxy Note 20 Ultra 5G and why?
Allisa [31]

Answer:

Samsung note 20 or iPhone but i think Samsung

Explanation:

8 0
3 years ago
Read 2 more answers
Which of the following code displays the area of a circle if the radius is positive. a. if (radius != 0) System.out.println(radi
maw [93]

Answer:

d. if (radius > 0) System.out.println(radius * radius * 3.14159);

Explanation:

The positive values are those values that are greater than 0(zero).0 is considered to be nonnegative number it is neither positive nor negative and for a zero radius the area will be 0.As we know the are of the circle is π*radius*radius, and π is 3.14159.So the correct answer matching to this condition is option d.

Which checks if the radius is greater than 0 then find the radius and print it.

8 0
4 years ago
Frank has created a résumé and separated the sections using headings. How can he set the headings apart from normal text?
Pepsi [2]
He could use bold or bigger text just a suggestion.
6 0
3 years ago
What is one similarity between compiled and interpreted programming languages? (5 points)
Rashid [163]

Answer:

Both compiled and interpreted languages are high-level languages and translate code for a computer to understand.

Explanation:

The one similarity between compiled and interpreted languages is that they are both high-level languages.

A high-level language is a computer language written in easy to understand human language which is then converted to machine code for the computer to understand.  

A high-level language can either be interpreted or compiled.

An interpreted is a language in which the code is translated line by line before execution while a compiled language is one in which the source code is converted directly into machine language before execution.

So, <u>the similarity between both languages is that they are high level languages and translate code for a computer to understand. </u>

8 0
2 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
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