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andreev551 [17]
2 years ago
5

"Name the property:a + (b+12) = (a+b) + 12"

Mathematics
1 answer:
vfiekz [6]2 years ago
8 0

Answer:

This property would be the Associative property of addition.



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Solve the system of 2x-5y+z=1 3 y+2z=5-24z=48
motikmotik
<span>A) 2x -5y +z = 1
B) 3 y + 2z = 5
C) -24 z = 48
Those 3 equations you typed were somewhat squished together.
Did I retype those correctly?
Let me know and I'll solve it.


</span>
8 0
3 years ago
Can you help me solve this question
IRINA_888 [86]

Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6

Step-by-step explanation:

a^2+b^2=c^2

3^2+2^2=c^2

9+4=c^2

13=c^2

3.6=c

3 0
2 years ago
If you earn $1200 per month and you expect your earnings to increase by 10% per year, what monthly salary would you be making in
Sergio [31]
So u turn the percent into a decimal.
0.10 
Now multiply 1200 * 0.10
1200*0.10= 120 ( 120 is the amount that is gonna increase)
So if it says 5 years, than your gonna multiply 120 * 5 
120*5 =600
So your gonna add 600 to 1200.
So in five years your gonna be making 1,800.
An easier way would be to use prt
Principle * rate * time
1200 * 0.10* 5
= 600
So now you just add 600 to 1200
= 1800

7 0
3 years ago
suppose y varies directly with x and y=5 when x=20. Write a direct variation equation then find the value of x when y=3/2
jek_recluse [69]
X=k*Y
K*Y=X
K=X/Y
K=20/5
K=4

For Y=3/2
X=k*3/2
X=4*3/2
X=6
6 0
3 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
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