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Mandarinka [93]
3 years ago
6

What is the value of the expression?

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0
<span>Asking the Math Gods...

you have no valid choices

300+34-(8*2)
=334-16
=318
</span>
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Find the measure of UT answer choice - 65 51 70 55​
muminat

Answer:

Option (4)

Step-by-step explanation:

If two chords intersect outside the circle, angle formed between the chords will be half of the sum of measures of intercepted arcs.

From the given picture,

m(\angle RQS)=\frac{1}{2}(m\hat{RS}+m\hat{UT})

95° = \frac{1}{2}(135+m\hat{UT})

190 = 135 + m(\hat{UT})

m(\hat{UT})=190-135

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6 0
3 years ago
Ammonia, nh3 (delta.hf = –46.2 kj), reacts with oxygen to produce water (delta.hf = –241.8 kj) and nitric oxide, no (delta.hf =
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The enthalpy change (ΔH) for the reaction given the data from the question is –900.8 KJ

<h3>Data obtained from the question</h3>
  • 4NH₃ + 5O₂ —> 6H₂O + 4NO
  • Enthalpy of ammonia, NH₃ = –46.2 KJ
  • Enthalpy of Oxygen = 0 KJ
  • Enthalpy of water, H₂O = –241.8 KJ
  • Enthalpy of nitric oxide, NO = 91.3 KJ
  • Enthalpy change (ΔH) =?

<h3>How to determine the enthalpy change</h3>

ΔHrxn = ∑ΔH(products) - ∑ΔH(reactants)

ΔHrxn = ∑[H(H₂O) + H(NO)] - ∑[H(NH₃) + H(O₂)]

ΔHrxn = [(6 × –241.8) + (4 × 91.3)] – [(4 × –46.2) + (5×0)]

ΔHrxn = –1085.6 + 184.8

ΔHrxn = –900.8 KJ

Learn more about enthalpy change:

brainly.com/question/2364362

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U sub 15 minus 8 and then u add
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