Here, the union tells us that at least one of the original inequalities must be true. We solve each separately, first.
x + 2 < 5 OR x - 7 > -6
x < 3 OR x - 7 > -6 subtract 2 on both sides of the equation left of the OR
x < 3 OR x > 1 add 7 on both sides of the equation right of the OR
Thus x < 3 or x > 1. In set notation, {x | x < 3 or x > 1} is true.
Answer54: A, 55: G, 56: D
Step-by-step explanation:
Y = 6 x² + 12 x - 10= 6 ( x² + 2 x ) - 10 = 6 ( ( x² + 2 x + 1 ) - 1 ) - 10=
6 ( x + 1 )² - 6 - 10 = 6 ( x + 1 )² - 16 ( vertex form)
About Reciprocal:
It's when a fraction is flipped.
Example:
- 2/3..... The reciprocal for 2/3 is 3/2.
- 3/5.... The reciprocal for 3/5 is 5/3.
Answer:
8000
Step-by-step explanation: