The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
f^-1 = 4(x-3)
Step-by-step explanation:
If f(x) = 1/4(x) + 3 we ned to find f^-1.
To find the inverse function, we need to solve the equation for "x", as follows:
f(x) = 1/4(x) + 3
y = 1/4(x) + 3
y-3 = 1/4(x)
4(y-3) = x
Now, change the "x" for an "y". And change the "y" for an "x":
4(x-3) = y
The solution is the last one.
Answer:
Area = 406
Step-by-step explanation:
First things first: Divide the shape
Here is how I did it:
21 x 16
14 x 5
Now solve:
21 x 16 = 336
14 x 5 = 70
Now add:
336 + 70 = 406
So the area is 406
