Ask question

Ask question

All categories

3 years ago

9

glenn raced his motorcycle 30 times last season. he finished first 12 times, second 5 times and crashed in 9 races. what percent

of races did he crash? set up a proportion and solve.

1 answer:

horrorfan [7]3 years ago

4 0

The percent he crashed was 33 percent

You might be interested in

What is one c o ck plus 2 c ock

lutik1710 [3]

Answer:

3 c ock

Step-by-step explanation:

Reason being of you add 1 c ock and 2 c ock you get 3 c ock

8 0

2 years ago

What is the range of f(x) = 4x?

antoniya [11.8K]

Range is all positive real numbers

answer is D. last one

8 0

3 years ago

Read 2 more answers

What are the answers to vocabulary check chapter review page 417?

UkoKoshka [18]

We need more information or a picture please :)

7 0

2 years ago

5) 5 ft<br> A) 38 ft<br> C) 18 ft<br> B) 15<br> D) 16 ft

Mrrafil [7]

Answer:

the answer is a

Step-by-step explanation:

3 0

2 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

6 months ago