Answer:
The value of h'(7) = 44 .
Step-by-step explanation:
Given:
f'(7)=9 and g(7)= 5
We have to find : h'(7)
Also,
⇔
...equation (i)
Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:
⇔ 
⇔ 
Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:
⇔ 
⇔ 
⇔ 
So the value of h=(7) = 44 .
Answer:
The answer can be find out by doing the following steps;
Step-by-step explanation:
Answer:
-2,4/3
Step-by-step explanation:
ax²+bx+c=0

Answer:
Step-by-step explanation:
f(x) = rad(x)
g(x) = 3rad(x)
Substitute f(x) = rad(x) in g(x)
So g(x) = 3f(x)
So it's a vertical stretch.