Answer:
Suppose that a couple invested $50,000 in an account when their child was born, to prepare for the child's college education. If the average interest rate is 4.4% compounded annually, ( A ) Give an exponential model for the situation, and ( B ) Will the money be doubled by the time the child turns 18 years old?
( A ) First picture signifies the growth of money per year.
( B ) Yes, the money will be doubled as it's maturity would be $108,537.29.
a = p(1 + \frac{r}{n} ) {}^{nt}a=p(1+
n
r
)
nt
a = 50.000.00(1 + \frac{0.044}{1} ) {}^{(1)(18)}a=50.000.00(1+
1
0.044
)
(1)(18)
a = 50.000.00(1 + 0.044) {}^{(1)(18)}a=50.000.00(1+0.044)
(1)(18)
a = 50.000.00(1.044) {}^{(18)}a=50.000.00(1.044)
(18)
50,000.00 ( 2.17074583287910578440507440 it did not round off as the exact decimal is needed.
a = 108.537.29a=108.537.29
Step-by-step explanation:
Hope This Help you!!
The ordered pairs for the intercepts are as follows:
x intercept = 9/2
y intercept = -18
In order to find either of these you must put 0's in for the other variable. So, to find the x intercept, we start by putting 0 in for y.
y = 4x - 18
0 = 4x - 18
-4x = -18
x = 9/2
To find the y intercept, we put a 0 in for x.
y = 4x - 18
y = 4(0) - 18
y = 0 - 18
y = -18
104 Because 100*4 = 400 and 4*4 = 16 so add together and get 416
Answer:
w < 8
Step-by-step explanation:
This means w can be any number below 8.
Example;
w = 7
w = 6
w = 5
and so on...
<em>(</em><em>Changed</em><em> </em><em>original</em><em> </em><em>answer</em><em>.</em><em> </em><em>Thought</em><em> </em><em>it</em><em> </em><em>had</em><em> </em><em>said</em><em> </em><em>-11</em><em> </em><em><</em><em> </em><em>w</em><em> </em><em>-</em><em> </em><em>1</em><em>9</em><em>)</em>
Answer:
OD.(x-3)(x-2)
Step-by-step explanation:
we need two numbers (negative ir positive) that multiply to get 6 abd add to get -5.
so its OD
as -3×-2=6
and -3+-2=-5
