Hi!
When you add a negative number, you really just subtract it. So let's solve this.
Convert the mixed numbers into improper fractions.

Solve
434 - 351 = 83

The sign of this fraction is positive
Hope this helps! :)
-Peredhel
Alright so the answer would be letter B, because
win-to-loss
49 to 21 (You can determine her losses by subtracted the number of wins from her total number of games played)
Now you must simplify your answer
7 is the greatest common factor (GCF) of both 49 and 21
Now divide both 49 and 21 by 7 to get
7 to 3
Surface Area of a cylinder 2(π•r²)+(2π•r)•h
So
If the diameter is 8 then the radius is 4. the height is 5.
so you have, 2(3.14•4²)+(2•3.14•4)•5
solve. PEMDAS
Parentheses & Exponents first.
2(3.14•16)+(2•3.14•4)•5
2(50.24)+(6.28•4)•5
2(50.24)+(25.12)•5
Multiplication & Division second (left to right)
100.48+125.6
Add & Subtract (left to right)
226.08cm
1 is A - just plug and chug
2 is B - for 2 linear equations to have infinite solutions they mustbe the same
3 is C
4 is C - that is where they intersect
5 is A - same slope and different intercepts means no solutions
Answer:
a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.
b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.
Step-by-step explanation:
In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

For n=25 we have:

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.
This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.
If n=50, we have:
