All categories

3 years ago

What does 5/9-1/12 equal to?

1 answer:

Elena-2011 [213]3 years ago

3 0

$\frac{5}{9} - \frac{1}{12} = \frac{5 \times 4}{9 \times 4} - \frac{1 \times 3}{12 \times 3}$
$= \frac{ 20}{36} - \frac{3}{36}$
$= \frac{17}{36}$

You might be interested in

Can someone help me asap!!!

amm1812

Answer:

<em>Negative</em>

Step-by-step explanation:

5 0

2 years ago

How do you do this? with work.

Rashid [163]

Answer:

i don't know

Step-by-step explanation:

so i have 20 the answer i thin

7 0

2 years ago

I need an explanation on how to do this and an answer, please.

Fudgin [204]

Answer:

111°

Step-by-step explanation:

the angle is question is an alternate-interior angle with the one labeled as 111° and alt-int angles are congruent

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BQuestion%3A%7D" id="TexFormula1" title="\huge\boxed{Question:}" alt="\huge\b

iragen [17]

The equivalent expression for (x + 4)^5 is $x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x + 1024$

The expression is given as:

$(x + 4)^5$

To expand the expression, we make use of Pascal triangle, where:

5:= 1 5 10 10 5 1

So, we have:

$(x + 4)^5 = 1 * x^5 * 4^0 + 5 * x^4 * 4^1 + 10 * x^3 * 4^2 + 10 * x^2 * 4^3 + 5 * x * 4^4 + 1 * x^0 * 4^5$

Evaluate the exponents

$(x + 4)^5 = 1 * x^5 * 1 + 5 * x^4 * 4 + 10 * x^3 * 16 + 10 * x^2 * 64 + 5 * x * 256 + 1 *1 * 1024$

Evaluate the products

$(x + 4)^5 = x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x + 1024$

Hence, the equivalent expression for (x + 4)^5 is $x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x + 1024$

Read more about binomial expressions at:

brainly.com/question/13602562

7 0

2 years ago

Read 2 more answers

I’m not very sure how to simplify the two bottom rows, can someone help me?

love history [14]

Answer:

The simplification is done below.

Step-by-step explanation:

$(\sin(\frac{\pi}{6})\cos(\frac{\pi}{4}) - \sin(\frac{\pi}{4})\cos(\frac{\pi}{6}))^{2}$

= $(\frac{1}{2} \times \frac{1}{\sqrt{2}} - \frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2})^{2}$

= $((\frac{1}{2\sqrt{2}}) \times (1 - \sqrt{3}))^{2}$

= $0.125 \times (1 - (2 \times \sqrt{3}) +3)$

5 0

3 years ago