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dedylja [7]
3 years ago
12

Barbara wanted to go into the long-distance trucking business. She bought a used tractor and trailer for $102,000. However, the

trailer wasn’t suitable for Barbara’s needs, so she sold it for $24,000 and purchased the trailer she needed for $30,000. What is Barbara’s basis in the tractor? What is Barbara’s basis in the trailer?
Business
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

Basis in the tractor 78.000 and new trailer basis 30.000

Explanation:

The adjusted basis is referred to as the cost basis of the assets as reduced by  the cost recovery amount including the depreciation at the point of sale. Alternatively, the adjusted basis can be termed as the unrealized cost basis of the assets. The formula for the adjusted basis is:

Adjusted basis = cost basis - Cost recovery deductions

The adjusted basis for B's tractor and trailer is calculated as follows:

Adjusted basis for tractor = Cost of tractor

=102.000 - 24.000

=78.000

Adjusted basis for new trailer = Cost of trailer

=30.000

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Answer:

b.$127,500 increase

Explanation:

Using Accounting Equation we can find thetotal increase in total assets:

Assets = Equity + Liabilities

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Change in Assets = $127,500

Total Change in equity and liabilities will be equal to the change in Assets.

So, the correct answer is b.$127,500 increase.

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3 years ago
You recently interviewed a candidate for a position in your sales department. However, another candidate was more qualified. You
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Answer:

B. Invite further correspondence.

C. Close with good wishes.

D. Buffer the opening.

Explanation:

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8 0
3 years ago
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Raggs, Ltd. a clothing​ firm, determines that in order to sell x​ suits, the price per suit must be p=120 - 0.5 x. It also deter
kodGreya [7K]

Answer:

A) R(x) = 120x - 0.5x^2

B) P(x) = - 0.75x^2 + 120x - 2500

C) 80

D) 2300

E) 80

Explanation:

Given the following :

Price of suit 'x' :

p = 120 - 0.5x

Cost of producing 'x' suits :

C(x)=2500 + 0.25 x^2

A) calculate total revenue 'R(x)'

Total Revenue = price × total quantity sold, If total quantity sold = 'x'

R(x) = (120 - 0.5x) * x

R(x) = 120x - 0.5x^2

B) Total profit, 'p(x)'

Profit = Total revenue - Cost of production

P(x) = R(x) - C(x)

P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)

P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2

P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500

P(x) = - 0.75x^2 + 120x - 2500

C) To maximize profit

Find the marginal profit 'p' (x)'

First derivative of p(x)

d/dx (p(x)) = - 2(0.75)x + 120

P'(x) = - 1.5x + 120

-1.5x + 120 = 0

-1.5x = - 120

x = 120 / 1.5

x = 80

D) maximum profit

P(x) = - 0.75x^2 + 120x - 2500

P(80) = - 0.75(80)^2 + 120(80) - 2500

= -0.75(6400) + 9600 - 2500

= -4800 + 9600 - 2500

= 2300

E) price per suit in other to maximize profit

P = 120 - 0.5x

P = 120 - 0.5(80)

P = 120 - 40

P = $80

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vesna_86 [32]

Answer:

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