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3 years ago

I What integer represents 6°F below zero?

Mathematics

1 answer:

NemiM [27]3 years ago

3 0

Answer:

Anything below zero is a negative integer, therefore, the answer would be

-6°F.

~ Hope this helps

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Determining whether an integer satisfies an inequality

Leto [7]

First we have - 6 < - 7 - 4x

Then we need to isolate the x of the inequality 4x < - 7 + 6

4x < - 1

x < - 1/4

The values less than - 1/4 are solutions for x

Btw if you need a tutor let me know:)

3 0

3 years ago

Lily has two times as much money invested in 8% stocks as she has in bonds paying 6%. How much she has invested in stocks if her

EleoNora [17]

Answer:

Final answer is $4440.

Step-by-step explanation:

Let amount of money invested in 8% stock = x

Let amount of money invested in 6% stock = y

then total money invested $325.6 gives equation

8% of x + 6% of y = 325.6

0.08x + 0.06y = 325.6

8x + 6y = 32560...(i)

other equation will be x=2y...(ii)

plug (ii) into (i)

8x + 6y = 32560

8(2y) + 6y = 32560

16y+ 6y = 32560

22y = 32560

$y=\frac{32560}{22}$

y=1480

plug y=1480 into (ii)

x=2y=2(1480)=2960

Then total money invested in stocks = x+y= 1480+2960=4440

Hence final answer is $4440.

5 0

3 years ago

Pls SHOW workings <br> It due ASAP

gavmur [86]

24. because if the length of PC is 8 then measure with your finger and you get thee but u have to mutiply 8 and 3 to get 24

4 0

3 years ago

Can someone help me with this

adell [148]

Answer:

Step-by-step explanation:

You divide 95 by 5 (because you have 5 times the amount), which is 19

6 0

3 years ago

Suppose that the number of customers that enter a bank in an hour is a Poisson random variable, and suppose that P(X = 0) = 0.09

Ksju [112]

Answer:

$E(X) = V(X) = 2.41$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In the Poisson distribution, the mean is the same as the variance.

P(X = 0) = 0.09

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-\mu}*\mu^{0}}{(0)!} = e^{-\mu}$

$e^{-\mu} = 0.09$

We apply ln to both sides, which is the inverse operation of the exponential.

$\ln{e^{-\mu}} = \ln{0.09}$

$-\mu = -2.41$

Multiplying by -1

$\mu = 2.41$

$E(X) = V(X) = 2.41$

8 0

3 years ago