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Kruka [31]
3 years ago
10

Translate these statements into english, where c(x) is “x is a comedian” and f (x) is “x is funny” and the domain consists of al

l people.
a.∀x(c(x) → f (x))
b.∀x(c(x) ∧ f (x))
c.∃x(c(x) → f (x))
d.∃x(c(x) ∧ f (x))
Mathematics
1 answer:
12345 [234]3 years ago
6 0
Fx                            dhg what is that?     
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Find the perimeter of the figure to the nearest hundredth. perimeter: about cm
nordsb [41]

The perimeter of the figure to the nearest hundredth is 50.26 cm.

<h3>Perimeter of a figure.</h3>

The perimeter of a figure is the sum of the whole sides of the figure.

The perimeter of the figure can be found as follows:

perimeter of the figure = 12 + 5 + 5 + circumference of the semi circle

circumference of the semi circle  = πr

where

  • r = radius

perimeter of the figure = 22 + πr

perimeter of the figure = 22 + 3.14(9)

perimeter of the figure = 22 + 28.26

perimeter of the figure = 50.26 cm

learn more on perimeter here: brainly.com/question/11419989

#SPJ1

6 0
2 years ago
I need qestion number d) solution please help me​
natita [175]

Answer:

It is an identity, the proof is in the explanation

Step-by-step explanation:

csc(A)-cot(A)=tan(A/2)

I'm going to start with right hand side

tan(A/2)=(1-cos(a))/(sin(a))                half angle identity

tan(A/2)=1/sin(a)-cos(a)/sin(a)         separate fraction

tan(A/2)=csc(a)-cot(a)                     reciprocal and quotient identities

8 0
3 years ago
Jim types 1800 words in 25 minutes. How many words does he type per minute
kirill [66]
1800 divided by 25 is 72. He types 72 words per minute.
3 0
3 years ago
To find the surface area of the pyramid, in square inches, Vikram wrote (33.2) (34.2) + 4 (one-half (34.2) (28.4)). What error d
madam [21]

Answer:

B. He used the wrong expression to represent the area of the base of the pyramid.

Step-by-step explanation:

Given

See attachment for pyramid

Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4

Required

Vikram's error

The surface area of a square pyramid is:

Area = Base\ Area + 4 * Area \triangle

Where

Base\ Area = Length * Length

Base\ Area = 34.2 * 34.2

4 * Area \triangle = 4 * \frac{1}{2} * Base * Height

4 * Area \triangle = 4 * \frac{1}{2} * 34.2 * 28.4

So:

Area = Base\ Area + 4 * Area \triangle

Area = 34.2 * 34.2 + 4 * \frac{1}{2} * 34.2 * 28.4

By comparing the calculated expression with

Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4

Option (b) is correct

3 0
2 years ago
What are the best approximations of the solutions to this system?
Scilla [17]

(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.

Option B

<u>Step-by-step explanation:</u>

Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:

First look at where we have intersection points, In first quadrant & in third quadrant.

<u>At first quadrant:</u>

Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)

<u>At Third quadrant:</u>

Draw perpendicular lines from x-axis & y-axis from this point. After doing this we can clearly see that the perpendicular lines cut x-axis at x=-1.2 and y-axis at y=  -2.0. So, other point is (-1.2,-2.0).

5 0
3 years ago
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