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3 years ago

A rhombus is a parallelogram with

Mathematics

2 answers:

ruslelena [56]3 years ago

5 0

Answer:

four congruent sides

lapo4ka [179]3 years ago

5 0

A rhombus is a parallelogram with four congruent sides .

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Which side lengths form a right triangle? Choose all answers that apply: Choose all answers that apply: (Choice A) A 3, 6, \sqrt

dlinn [17]

Answer:

A, B and C

Step-by-step explanation:

Given any three side lengths of a right triangle, the longest side is the hypotenuse.

The side lengths of a right triangle must satisfy the Pythagorean Theorem.

Pythagorean Theorem: $Hypotenuse^2=Opposite^2+Adjacent^2$

Option A: $3, 6, \sqrt{45}$

$(\sqrt{45})^2=3^2+6^2\\45=36+9\\45=45$

True

Option B: 2.5, 6, 6.5

$6.5^2=6^2+2.5^2\\42.25=36+6.25\\42.25=42.25 (TRUE)$

Option C: $4, 8, \sqrt{80}$

$4, 8, \sqrt{80}\\( \sqrt{80})^2=4^2+8^2\\80=16+64\\80=80 (TRUE)$

Since all are true, the side lengths in Options A, B and C forms a right triangle,

4 0

3 years ago

PLEASE HELP ME OUT IM FAILING MATH

MrMuchimi

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Evaluate the piecewise function for the given values.

adoni [48]

Answer:

f(-3) = -2

f(-2.6) = -2

f(0.6) = 2.4

f(4.5) = 8.5

Step-by-step explanation:

(Whole question:

Evaluate the piecewise function for the given values.

Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)

As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.

So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2

For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2

For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4

For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5

5 0

3 years ago

Write a quadratic function in standard form having zeros of -9 and -12

tia_tia [17]

(x + 9)(x + 12) = 0
Expanding the brackets, we get:
$x^{2}+21x+108=0$

3 0

3 years ago

Please help me 33/2 + 3y/5 = 7y/10 + 15

8090 [49]

We are given with an equation in variable y and we need to solve for y . So , now let's start !!!

We are given with ;

${:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}$

Take LCM on both sides :

${:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}$

Multiplying both sides by 10 ;

${:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}$

${:\implies \quad \sf 165+6y=7y+150}$

Can be further written as ;

${:\implies \quad \sf 7y+150=165+6y}$

Transposing 6y to LHS and 150 to RHS

${:\implies \quad \sf 7y-6y=165-150}$

${:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}$

8 0

2 years ago