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3 years ago

A = 7+10n help me plz

Mathematics

1 answer:

Marrrta [24]3 years ago

3 0

Answer:

I'll help you out. Question: Are you solving for A or for N?

If you're solving for A: A=10n + 7

If you're solving for N: Isolate the variable by dividing each side by factors that don't contain the variable. n = A/10 - 7/10

Hope this helped!

Step-by-step explanation:

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The answer is b,

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Can anybody help me with any of these problems please

Artist 52 [7]

Answer:

Part 9) $x=7$

Part 10) $m\angle Y=92^o$

Part 11) $x=5$

Part 12)

$m\angle 1=60^o$

$m\angle 2=41^o$

$m\angle 3=19^o$

$m\angle 4=41^o$

$m\angle 5=19^o$

Part 13) The measure of each side is 56 units

Part 14)

$x=10/3$

$HI=12\ units$

$HJ=12\ units$

$IJ=38/3\ units$

Part 15)

$x=7$

$m\angle C=41^o$

$m\angle D=41^o$

$m\angle A=98^o$

Step-by-step explanation:

Part 9) we know that

An isosceles triangle has two equal sides and two equal interior angles

The triangle of the problem is an isosceles triangle

Because has two equal sides and two equal angles

Remember

The sum of the interior angles in any triangle must be equal to 180 degrees

$2(8x-4)^o+76^o=180^o$

solve for x

$16x-8+76=180\\16x=180-68\\16x=112\\x=7$

Part 10) we know that

step 1

Solve for x

An isosceles triangle has two equal sides and two equal interior angles

The triangle XYZ of the problem is an isosceles triangle

Because has two equal sides

$m\angle X=m\angle Z$

substitute the given values

$(4x-12)^o=(2x+16)^o$

solve for x

$4x-2x=16+12\\2x=28\\x=14$

Find the measure of angle X

$m\angle X=(4x-12)^o$

substitute the value of x

$m\angle X=(4(14)-12)=44^o$

$m\angle Z=44^o$

step 2

Find the measure of angle Y

Remember

The sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle Y+2(44^o)=180^o$

$m\angle Y=180^o-88^o=92^o$

Part 11) we know that

we know that

An equilateral triangle has three equal sides and three equal interior angles. The measure of each interior angle is 60 degrees

In this problem we have an equilateral triangle

$(14x-10)^o=60^o$

solve for x

$14x=60+10\\14x=70\\x=5$

Part 12)

step 1

Find the measure of angle 1

we know that

An equilateral triangle has three equal sides and three equal interior angles. The measure of each interior angle is 60 degrees

In this problem the triangle WXY is an equilateral triangle

therefore

$m\angle 1=60^o$

step 2

Find the measure of angle 3

we know that

Triangle WZY is an isosceles triangle

$m\angle 3=m\angle 5$

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle 3+m\angle 5+142^o=180^o$

$2m\angle 3=180^o-142^o$

$m\angle 3=19^o$

$m\angle 5=19^o$

step 3

Find the measure of angle 2

we know that

The measure of each interior angle of an equilateral triangle is equal to 60 degrees

$m\angle 2+m\angle 3=60^o$

substitute the given value

$m\angle 2+19^o=60^o$

$m\angle 2=60^o-19^o$

$m\angle 2=41^o$

step 4

Find the measure of angle 4

we know that

The measure of each interior angle of an equilateral triangle is equal to 60 degrees

$m\angle 4+m\angle 5=60^o$

substitute the given value

$m\angle 4+19^o=60^o$

$m\angle 4=60^o-19^o$

$m\angle 4=41^o$

Part 13) we know that

we know that

An equilateral triangle has three equal sides and three equal interior angles. The measure of each interior angle is 60 degrees

AB=BC=AC

solve the equation

AB=BC

substitute the given values

$5x-9=7x-35\\7x-5x=35-9\\2x=26\\x=13$

Find the measure of side AB

$AB=5x-9$

substitute the value of x

$AB=5(13)-9=56\ units$

Verify BC and AC

$BC=7(13)-35=56\ units$ ----> is correct

$AC=4(13)+4=56\ units$ ----> is correct

Part 14) we know that

An isosceles triangle has two equal sides and two equal angles

In this problem Triangle HIJ is an isosceles triangle

because

Angle I is equal to Angle J

HI=HJ

substitute the given values

$6x-8=3x+2$

solve for x

$6x-3x=2+8\\3x=10\\x=10/3$

Find the measure of each side

$HI=6(10/3) -8=12\ units$

$HJ=3(10/3)+2=12\ units$

$IJ=5(10/3)-4=38/3\ units$

Part 15) we know that

Triangle ACD is an isosceles triangle

because

has two equal sides

AC=AD

$m\angle C=m\angle D$

substitute the given values

$6x-1=7x-8$

solve for x

$7x-6x=8-1\\x=7$

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$m\angle C=6(7)-1=41^o$

Find the measure of angle D

$m\angle D=7(7)-8=41^o$

Find the measure of angle A

we have that

$m\angle C+m\angle D+m\angle A=180^o$

substitute

$41^o+41^o+m\angle A=180^o$

$m\angle A=180^o-82^o$

$m\angle A=98^o$

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Answer:

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Step-by-step explanation:

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anzhelika [568]

Answer: True

=========================================================

Explanation:

If you meant to say $f(x) = \frac{2x+3}{x^2-4}$ , then we cannot have x^2-4 equal to 0

We can never have 0 in the denominator.

Set the expression equal to 0 and solve for x

x^2 - 4 = 0

(x-2)(x+2) = 0 .... difference of squares rule

x-2 = 0 or x+2 = 0

x = 2 or x = -2

So if either x = 2 or x = -2, then we have x^2-4 equal to zero.

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In short, the restrictions for x are 2 and -2. That's why the statement is true.

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3 years ago

A = 7+10n help me plz​

A = 7+10n help me plz