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Goshia [24]
3 years ago
8

Here are 9 members on a board of directors. if they must elect a chairperson, a secretary, and a treasurer, how many different s

lates of candidates are possible?
Mathematics
1 answer:
padilas [110]3 years ago
7 0
Slot A = chairperson position
Slot B = secretary position
Slot C = treasurer position

There are 9 choices for slot A. After picking that person, there are 8 choices for slot B. Then 7 choices for slot C

Multiply those values out: 9*8*7 = 72*7 = 504

There are 504 ways to pick three people from a pool of nine.

Answer: 504

Note: order matters so this is a permutation. You can use the nPr permutation formula with n = 9 and r = 3 to get the same answer
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* WORTH 30 Points *
yawa3891 [41]
Any multiple of (-2x+3y=18) would constitute an "other equation" forming a system with an infiinite number of solutions.  The reason for that is that the two equations would be "dependent."

On the other hand, looking at the system

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we see that there is no solution.  Why?  Because -2x + 3y cannot equal 18 and 19 at the same time.  You'd have two non-intersecting, parallel lines.

</span>
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