Because you have two variables and only one equation, you can only solve for approximate answers, and not complete, absolute answers.
<h3><u>You can simplify this equation to x = -4y + 12</u></h3>
y - 3 = -1/4(x + 3)
Distributive property.
y - 3 = -1/4x - 3/4
Multiply all terms by 4.
4y - 12 = -x
Multiply all terms by -1
-4y + 12 = x
Answer:
1/3
Step-by-step explanation:
When working with balanced expressions (stuff on both sides of the equal sign), "what you do to one side, you do to the other", which keeps it balanced.
The first thing we notice is the exponent 1/4, which is one both sides, so we can get rid of it on both sides by using the <u>reverse operation</u>.
The reverse of exponents is <u>square root</u>.
![(4x + 10)^{\frac{1}{4}} = (9 + 7x)^{\frac{1}{4}}\\\sqrt[\frac{1}{4}]{(4x + 10)^{\frac{1}{4}}} = \sqrt[\frac{1}{4}]{(9 + 7x)^{\frac{1}{4}}}\\\\4x + 10 = 9 + 7x](https://tex.z-dn.net/?f=%284x%20%2B%2010%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%3D%20%289%20%2B%207x%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%5Csqrt%5B%5Cfrac%7B1%7D%7B4%7D%5D%7B%284x%20%2B%2010%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%20%3D%20%5Csqrt%5B%5Cfrac%7B1%7D%7B4%7D%5D%7B%289%20%2B%207x%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5C%5C%5C%5C4x%20%2B%2010%20%3D%209%20%2B%207x)
Isolate x to solve. Separate the variables and non-variables.
4x + 10 = 9 + 7x
4x - 4x + 10 = 9 + 7x - 4x Subtract 4x from both sides
10 = 9 + 3x
10 - 9 = 9 - 9 + 3x Subtract 9 from both sides
1 = 3x Divide both sides by 3 to isolate x
x = 1/3 Answer
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Step-by-step explanation:
Let's represent the two integers with the variables 
and 
.
From the problem statement, we can create the following two equations:
With the first equation, we can subtract from both sides to isolate the variable to the left-hand side:
Now that we have a value for , we can plug it into the second equation and solve for :
Now, let's move everything to one side of the equation:
Factoring this quadratic will give us two values for :
Since we now know , we can plug this back into either of the original equations to get a value for , which will be 
.
So the two numbers that sum to 
and have a product of 
are 
.
Isolate the x. Subtract 4x from both sides, and add 2 to both sides
2x (-4x) - 2 (+2) > 4x (-4x) + 6 (+2)
2x - 4x > 6 + 2
Simplify. Combine like terms
-2x > 8
Isolate the x. Divide -2 from both sides. Note that you are <em>dividing a negative number</em>. When doing so, flip the sign.
-2x/-2 > 8/-2
x > 8/-2
x < -4
x < -4, or (1) is your answer
hope this helps
