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erastova [34]
3 years ago
7

n 1917 the cost of a first-class postage stamp was 3¢. In 1974 the cost for a first-class postage stamp was 10¢. What is the per

cent of increase in the cost of a first-class postage stamp?
Mathematics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

233.33 %.

Step-by-step explanation:

The increase is 10 - 3 = 7c.

Percentage increase =  100 * 7 / 3.

= 700 / 3

=  233.33 %.

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Josiue tosses a coin and spins the spinner at the right. What are all the possible outcomes?
vazorg [7]
The possible outcomes for the coin is 2 out of 1 since a coin has 2 sides the coin may only land on 1 side but the chances are between both sides having a 50/50 chance to land on either side.
6 0
3 years ago
What is the slope of this line? y = -3/4 x + 7/8
Alexeev081 [22]
I am sorry I can help more but
Google can graph lines if that helps

You just look up graph of a line with your numbers
7 0
3 years ago
29. Find the height of the trapezoid. Use this height to find the area. (A =
harkovskaia [24]

Answer:

<em>The area of the trapezium is 168</em>

Step-by-step explanation:

<u>Area of a Trapezoid</u>

Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:

\displaystyle A=\frac{b_1+b_2}{2}h

The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:

10^2=EC^2+BC^2

The side BC can be found as half the difference of the bases:

BC=\frac{27-15}{2}=6

Solving for EC:

EC^2=10^2-6^2=100-36=64

EC=\sqrt{64}=8

Now we have the height, calculate the area:

\displaystyle A=\frac{15+27}{2}*8

\displaystyle A=\frac{42}{2}*8

A = 168

The area of the trapezium is 168

5 0
2 years ago
Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b
Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A =  (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

Slope, m \, of \. base, \, AC= \frac{dy}{dx}  = \frac{b - b}{a - (-a)}  = \frac{0}{2\cdot a} = 0

Hence, segment AC is vertical

Slope, m \, of \, segment \ CP \,  joining \, vertex, \, to \, midpoint, P, on  \,AC = \frac{0 - b}{0 - 0}  = \frac{-b}{0} = Undifined.

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

6 0
3 years ago
What is the greatest common factor of 15, 75, and 9
Leokris [45]

Answer:

3

Step-by-step explanation:

please mark Brainliest

3 0
3 years ago
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