I think 45 because if you look at the top of the other 45 the graphs look the same lengths except this one stretches out so 45°
Since he started with Nothing
He had zero initially
After x Months...
He'll have 10x naxvips
in slope intercept form
y=10x
To get the y values ... substitute the corresponding x value
For x=0
y=10(0)
y=0. Which is true cos he had no naxvip initially
x=1
y=10(1)
=10. Which is true cos he buys 10 more monthly... So 10 + 0 = 10.
x=2
y=10(2) = 20. This is true cos he added an additional 10 after each month
x=7
y=70.
Well just think 747 divided by 9
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!