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Jobisdone [24]
3 years ago
15

Rachel is packing up her room to move to a new city.Together,all the books on her bookshelf weigh 85 pounds.She wants to divide

the books among 4 boxes,so that each box will weigh the same amount.
How many pounds of books will be in each box?
Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

21.25

Step-by-step explanation:

85/4 = 80/4+5/4 = 20 + 1 + 1/4 = 21 + 0.25 = 21.25

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Find the area of a square with a side of 20m
ch4aika [34]
The area of a square is: A = s^2

With side being s = 20m

A = 20^2m^2 = 400m^2

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The scatter plot would closely resemble a straight line with a negative slope. The data has a strong, negative correlation, and a causal relationship exists between the team playing at home and winning.

Step-by-step explanation:

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Explain why the two equations below have the same solutions. x + 3y = −1 −2x − 6y = 2
Aloiza [94]
X + 3y= -1
-2x - 6y = 2

These two equations have the same solution because we can see that they are equivalent. 

One way to find out is this:-

Since x has a +1 next to it, and the other equation has a (-2) next to the x, we can multiply everything on the first equation by 2 to see if they are equivalent.

x+3y= -1
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7 0
3 years ago
Question
krok68 [10]

Answer:

Acute angle between the two planes: approximately 43^\circ.

Step-by-step explanation:

Find the normal vector of each plane:

  • The normal vector of the plane x - 2\, y + 5\, z = 3 is \displaystyle \begin{bmatrix}1 \\ -2 \\ 5\end{bmatrix}.
  • The normal vector of the plane 2\, x + y - 3\, z = 15 is \displaystyle \begin{bmatrix}2 \\ 1\\ -3\end{bmatrix}.

As the name suggests, there is a 90^\circ angle between a plane and its normal vector. The following four angles will correspond to the vertices of a quadrilateral:

  • The 90^\circ angle between the first plane and its normal vector.
  • The angle between the normal vector of each plane.
  • The 90^\circ angle between the second plane and its normal vector.
  • The smallest angle between these two planes.

The sum of these four angles should be 360^\circ. Two of these four angles were known to be 90^\circ. Once the third angle (the angle between the two normal vectors) is found, subtractions would give the measure of the other angle (the smallest angle between these two planes.)

Make use of the dot product to find the angle between these two normal vectors. Let \theta denote the angle between these two vectors.

\displaystyle \cos \theta = \frac{\begin{bmatrix}1 \\ -2 \\ 5\end{bmatrix} \cdot \begin{bmatrix}2 \\ 1 \\ -3\end{bmatrix}}{\sqrt{1^2 + (-2)^2 + 5^2} \cdot \sqrt{2^2 + 1^2 + (-3)^2}} \approx -0.73193.

Before continuing, notice that the smallest angle between the two planes would be 360^\circ - 90^\circ - 90^\circ - \theta = 180^\circ - \theta.

Consider the identity: \cos\left(180^\circ - \theta\right) = -\cos \theta.

In other words, \cos\left(180^\circ - \theta\right), the cosine of the smallest angle between the two planes (which the question is asking for) will be the opposite of \cos \theta, the cosine of the angle between the two normal vectors.

Therefore, the cosine of the smallest angle between the two planes will be -(-0.73193) = 0.73193.

Apply the inverse cosine function to find the size of that angle:

\arccos(0.73193) \approx 43^\circ.

8 0
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Which expression is a polynomial?
PtichkaEL [24]
The answer is B. 
There is more than one term
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