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3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

Mathematics

1 answer:

nirvana33 [79]3 years ago

8 0

Answer:

<KLN and <MLI

Step-by-step explanation:

vertical angles are made by opposite angles that are made by two intersecting lines

hope this helps :), brainliest??

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Please show work 7r + 21 = 49r

gulaghasi [49]

Answer:

1/2 = r

Step-by-step explanation:

7r + 21 = 49r

Subtract 7r from each side

7r-7r + 21 = 49r-7r

21 = 42r

Divide each side by 2

21/42 = 42r/42

1/2 = r

5 0

3 years ago

Read 2 more answers

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

3 years ago

This??? What is wrong with it?

ELEN [110]

Answer:

15.8 sq. in. of paper will be required.

Step-by-step explanation:

The problem is that a drinking cup does not have a cover, so only the lateral surface area counts.

I.e. We need only the first term.

A = pi r l = pi * 1.5 * sqrt(3^2+1.5^2)

= 15.81 sq. in.

4 0

3 years ago

Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12

BARSIC [14]

We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.

Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.

A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.

$\text{Mean age of players}=\frac{10+11+11+12+12+12+12+12+13+13+13+14}{12}$