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3 years ago

The volume of a prism is 45 km3. What would change if the volume of the prism were measured in cubic meters?

2 answers:

8 0

The volume of the prism stays the same, but the number representing the volume increases because cubic meters converted to km is 1e-9

Leya [2.2K]3 years ago

7 0

Ans is <span>The volume of the prism stays the same, but the number representing the volume increases as m3 << km3

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URGENT!! DUE IN 15 MIN!!<br> *don't mind the answer I chose*

prisoha [69]

I think its D but im not sure

8 0

2 years ago

Read 2 more answers

If a solid cube has a density of 6.3 grams per millimeter and a volume of 30 millimeters, how much is it's mass?

agasfer [191]

density= mass/volume

mass= densiy x volume

mass= 6.3 g/mm^3 x 30mm^3= 189 g

8 0

3 years ago

The x- intercept is the ________ to a function or group

Svetach [21]

Answer:

is the point

Step-by-step explanation:

...............

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3 years ago

Alex started a new social media account,which he used to post pictures of cute animals. On the first day he only had 8 followers

Hatshy [7]

Answer:

648 followers

Step-by-step explanation:

Let first day=a1

Tripled followers everyday

Second day=a2=a1×3

Third day=a3=a2*3

Fourth day=a4=a3*3

Fifth day=a5=a4*3

a=8 followers

a2=a1×3

=3*8

=24 followers

a3=a2*3

=24*3

=72 followers

a4=a3*3

=72*3

=216 followers

a5=a4*3

=216*3

=648 followers

On the fifth day, Alex will have a total of 648 followers on his new social media account.

7 0

3 years ago

Refer to the accompanying TI-83/84 Plus calculator display of a 95% confidence interval. The sample display results from using

Darina [25.2K]

Answer:

[22.57 ± 2.776]

Step-by-step explanation:

Hello!

You have the 95% Confidence Z-interval (21.182;23.958), the mean X[bar]= 22.57 and the sample size n=25.

The formula for the Z interval is

[X[bar] ± $Z_{1-\alpha /2} *( \frac{Sigma}{\sqrt{n} } )$ ]

The value of Z comes from tha standard normal table:

$Z_{1-\alpha /2} = Z_{0.975}= 1.96$

The semiamplitude (d) or margin of error (E) of the interval is:

E or d= (Upperbond- Lowerbond)/2 = (23.958-21.182)/2 = 2.776

[X[bar] ± E]

[22.57 ± 2.776]

I hope it helps!

8 0

2 years ago