Mikes cookie recipe needs 3/4 cup of sugar. Jans recipe needs 1/2 cup of sugar. How much more sugar does mike need than Jan?

900 students took 18 buses to the museum. on average, how many students rode each bus?

maks197457 [2]

900/18=50
On average, 50 students rode each bus
Hope this helps!

8 0

3 years ago

PLEASE HELP.

pentagon [3]

Let x represent the number of shirts. Let y represent the number of pens.

If shirts are on sale for $11.99 each, then x shirts cost $11.99x.

If pants are on sale for $12.99 each, then y pants cost $12.99y.

The total cost is $(11.99x+12.99y).

Sarah can spend up to $65. Then an inequality that represents this situation is

11.99x+12.99y≤65 (this inequality holds when Sarah can spend $65 too)

or

11.99x+12.99y<65 (this inequality holds when Sarah can spend less than $65).

3 0

3 years ago

What is the value of z? <br> 4z+3=8

Anika [276]

Answer:

z = 1.25

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the accumulated value of an investment of for years at an interest rate of if the money is a. compounded semiannually; b.

neonofarm [45]

Answer:

I dont know ask your mom or dad or sum to help u-

Step-by-step explanation:

3 0

2 years ago

The mayor of a town has proposed a plan for the annexation of a new bridge. A political study took a sample of 1000 voters in th

garri49 [273]

Answer:

$z=\frac{0.42 -0.39}{\sqrt{\frac{0.39(1-0.39)}{1000}}}=1.945$

$p_v =P(Z>1.945)=0.0259$

If we compare the p value obtained with the significance level given $\alpha=0.02$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 2% of significance the proportion of residents who favored annexation is not significantly higher than 0.39.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

$\hat p=0.42$ estimated proportion of residents who favored annexation

$p_o=0.39$ is the value that we want to test

$\alpha=0.02$ represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.39:

Null hypothesis: $p\leq 0.39$

Alternative hypothesis: $p > 0.39$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.39}{\sqrt{\frac{0.39(1-0.39)}{1000}}}=1.945$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.02$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>1.945)=0.0259$

If we compare the p value obtained with the significance level given $\alpha=0.02$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 2% of significance the proportion of residents who favored annexation is not significantly higher than 0.39.

4 0

3 years ago