QUESTION 2
1 answer:
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Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.
(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic =
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer: -9 degrees Fahrenheit
Step-by-step explanation:
Given: Temperature at 6:00 AM = -12 degrees Fahrenheit
Temperature increased each hour = degrees Fahrenheit
Temperature increase in 6 hours =
Temperature at noon = Temperature at 6:00 AM+Temperature increase in 6 hours
= -12+3 degrees Fahrenheit
= -9 degrees Fahrenheit
Hence, the temperature in degrees Fahrenheit at noon= -9 degrees Fahrenheit