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CaHeK987 [17]
3 years ago
10

Simplify: -2 (x - 5) + 6x

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Answer:

The answer is 4x+10

Step-by-step explanation:

-2(x-5)+6x= -2x+10+6x

                =4x+10

Ulleksa [173]3 years ago
4 0

Answer:

4x +10

Step-by-step explanation:

-2(x-5) +6x

-2x +10 +6x

4x +10

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What is 45/1000 reduced?
Anna35 [415]
9/200. divide 45 and 1000 both by 5 to reduce it.
8 0
3 years ago
Write the exponential function that passes through the points (3, 10) and (5, 40)
tigry1 [53]

Answer:

  y = (5/4)2^x

Step-by-step explanation:

The function value increases by a factor of 40/10 = 4 when x increases by 2. The function can be written as ...

  y = (reference value)·(growth factor)^((x -reference)/(change in x for growth factor))

  y = 10·4^((x-3)/2) . . . . . . using point (3, 10) as a reference

This can be simplified to ...

  y = 10·2^(x -3) = 10/8·2^x

  y = (5/4)2^x

6 0
3 years ago
2n-7/3 = 15 solve for n
WITCHER [35]
2n- \frac{7}{3} =15 
2n- \frac{7}{3} =15  common denominator is 3
3(2n- \frac{7}{3} )=3*15 distributhing  3 through parantheses
3*2n- \frac{3*7}{3}=3*15
3*2n-7=3*15
6n-7=45   add7
6n=45+7
6n=52 divide by 6
n= \frac{52}{6} simplify
n=8 \frac{2}{3} ⇒ \frac{26}{3}
5 0
3 years ago
What is the greatest common factor of 49 and 84? a3 b4 c7 d9
Brilliant_brown [7]

Hi There!

Answer: c. 7

Why: 84 / 7 = 12 and 49 / 7 = 7

Hope This Helps :)

5 0
2 years ago
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
2 years ago
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