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Anit [1.1K]
4 years ago
12

What is 29/12 as a mixed number

Mathematics
2 answers:
Marizza181 [45]4 years ago
8 0
The answer to your question is 2 5/12. I hope this was a big help and I hope this is right!
morpeh [17]4 years ago
6 0
The answer to your question is 2 and 5/12
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A parabola opening upward shifted 7 units rights and 4 units down
Sati [7]

Answer:

y + 4 = a(x - 7)^2

Step-by-step explanation:

The standard vertex form of a parabola with vertex at (h, k) is

y - k = a(x - h)^2

and if we start with the simplest case, y = a(x)^2 and translate its graph 7 units to the right and 4 units down, we get   y - {-4] = a(x - 7)^2, or

y + 4 = a(x - 7)^2

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3 years ago
Help on problem 11 plz
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Dalam suatu perlombaan seorang pembalap sepeda menempuh lintasan berbentuk lingkaran dengan jari jari 500 mjika pembalap tersebut menempuh jarak 15.700 m maka jumlah putaran yang di tempyh...
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4 years ago
Steven earns extra money babysitting he charges $33 for 4 hours and $57.75 for 7 hours entering an equation to represent the rel
sweet [91]

Answer:

<em>y = 8.25x</em>

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If a situation comes where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

y=mx+b

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Let's use linear modeling to represent Steven's earnings he makes babysitting. Call y the money he charges by x hours of work.

We know he charges y1=$33 for x1=4 hours, and y2=$57.75 for x2=7 hours. The ordered pairs are (4,33) and ( 7, 57.75)

Computing the equation of the line we have:

\displaystyle y-33=\frac{57.75-33}{7-4}(x-4)

Operating:

\displaystyle y-33=\frac{24.75}{3}(x-4)

y - 33 = 8.25( x - 4 )

y = 8.25x - 33 + 33

y = 8.25x

There is a proportional relationship.

6 0
3 years ago
I need help on this ​
tatuchka [14]

Answer:

hjkasdjhassd

Step-by-step explanation:

6 0
3 years ago
Find the general form, Ax2+Ay2+Dx+Ey+F=0, by identifying the coefficients A,D,E,&amp;F center:(0,1); r=1 (x-0)2+(y-1)2=1 x2+y2-2
siniylev [52]

Answer:

The value of A is 1, D is 0, E is -2 and F is 0.

Step-by-step explanation:

The given equation is

Ax^2+Ay^2+Dx+Ey+F=0             ...(1)

The standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius.

(x-0)^2+(y-1)^2=1

x^2+y^2-2y+1-1=0

x^2+y^2-2y=0

It can be written as

x^2+y^2+0x-2y+0=0                          ....(2)

On comparing (1) and (2) we get.

A=1

D=0

E=-2

F=0

Therefore the value of A is 1, D is 0, E is -2 and F is 0.

6 0
4 years ago
Read 2 more answers
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