Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
domain - (-infinity,infinity)
range - (-infinity, 2]
axis of sym - x=-1
y int - (0,-1)
at what value (row 1) - (-1,2)
Step-by-step explanation:
domain is side to side, it never ends bc of the arrows
range is top to bottom, there is no bottom bc of the arrow, but it has a top at 2 (the value on the y axis)
the axis of sym is basically the line that runs through the vertex, it's where you could fold it in half and it would still match up
Answer:
h=69
Step-by-step explanation:
H=VM2 +69=Y.......
