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Brrunno [24]
4 years ago
13

I'm stuck on this question would like some help

Mathematics
1 answer:
AveGali [126]4 years ago
4 0
-1.25

Use distributive property.
7u-7=9u+6+10u+2

7u-7=19u+8

-7=12u+8

-15=12u

-1.25=u

u= -1.25
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Step-by-step explanation:

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In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t
Basile [38]

So, since averages are defined as:

\frac{\sum_{k=1}^{P} P_k}{P}=70

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

\frac{\sum_{k=1}^{N} N_k}{N}=70

We can take both of these equations and multiply them by N:

\sum_{k=1}^{P} P_k=70P

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So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

\frac{\sum_{k=1}^{P} P_k+\sum_{k=1}^{N}N_k}{N+P}=\frac{70P+92N}{N+P}

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

86=\frac{92N+70P}{N+P} \implies\\ 86N+86P=92N+70P \implies \\ 16P=6N \implies \\ \frac{16P}{N}=6 \implies \\ \frac{P}{N}=\frac{6}{16}

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7 0
4 years ago
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ki77a [65]

Answer:

Option c. integers from 1 to 10 inclusive.

Step-by-step explanation:

The given sets are A = { 1, 3, 5, 7, 9 }

                               B = { 2, 4, 6, 8, 10 }

                               C = { 1, 5, 6, 7, 9 }

We have to determine A ∪ B

A ∪ B = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }

Therefore, A ∪ B is the set of all from 1 to 10 inclusive.

option C will be the answer.

6 0
3 years ago
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Setler79 [48]

Answer:

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Step-by-step explanation:

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3 years ago
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