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Nataly [62]
3 years ago
10

A = {1, 3, 5, 7, 9}

Mathematics
1 answer:
ki77a [65]3 years ago
6 0

Answer:

Option c. integers from 1 to 10 inclusive.

Step-by-step explanation:

The given sets are A = { 1, 3, 5, 7, 9 }

                               B = { 2, 4, 6, 8, 10 }

                               C = { 1, 5, 6, 7, 9 }

We have to determine A ∪ B

A ∪ B = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }

Therefore, A ∪ B is the set of all from 1 to 10 inclusive.

option C will be the answer.

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What is the solution to this system of equations?
Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

5(2)-2(-6)+2(1)=24

10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2  together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

x=2

Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

3+y=-3

Subtract 3 on both sides:

y=-6

So the solution is (x=2,y=-6,z=1).

8 0
3 years ago
G^4+ 5h<br> when g=2 &amp; h=4
il63 [147K]

Answer: <em>36</em>

<em />

Step-by-step explanation:

<em>g^4+5h</em>

<em>2</em><em>^4+5(</em><em>4</em><em>)</em>

<em>16+20</em>

<em>36</em>

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Rainbow [258]
Answer:

8 1/8

Step-by-step explanation:

V = 16 1/4 • 1/2

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3 years ago
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