Is 1 2/6 an irrational number

Please answer this correctly without making mistakes

boyakko [2]

Answer:

105/4 or 26.25 mi

Step-by-step explanation:

hillsdale to fairfax 8 7/8 = 71/8

fairfax to yardley = 17 3/8 = 139/8

71/8 + 139/8 = 105/4 or 26 2/8

7 0

3 years ago

What value of x makes this equation true?

UkoKoshka [18]

Answer:

The correct answer is D

Step-by-step explanation:

-190 + -100 = -290

190 + -100 = 90

-10 + -100 = -110

10 + -100 = 90

✩brainliest appreciated✩

8 0

2 years ago

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A person, who decided to go to weekend trip should not exceed 8 hours driving in a day. Average speed of forward journey is 60 k

Paraphin [41]

Since he must not exceed 8 hours driving in a day:
Let the distance of the picnic be = x km.

Therefore time for forward journey = x / 60
Return journey    = x / 50

The total trip should not exceed 8 hours.
Therefore: x / 60 + x / 50 <= 8.    LCM = 300

Taking LCM and multiplying on both sides:
5x + 6x <= 8(300)
   11x <= 2400
   x <= 2400/11
   x   <= 218.18
The picnic spot must be less than or equal to 218.18 km.

5 0

3 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

Line M is represented by the following equation: x − y = 8

PIT_PIT [208]

Let's plug in (18,10) into each answer choice until we find the one that has it as a solution.

A) 2x - y = 26
2(18) - 10 = 26
36 - 10 = 26
26 = 26

Your answer is A.

I'll just do the rest to show that you the they are incorrect.

B) x + y = 18
18 + 10 = 18
28 ≠ 18

C) 2x - 2y = 36
2(18) - 2(10) = 36
36 - 20 = 36
16 ≠ 36

D) x - y = -28
18 - 10 = -28
8 ≠ -28

Your answer is A) 2x - y = 26.

6 0

3 years ago

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