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Maksim231197 [3]
2 years ago
5

29.?? + 1.4 2. ??.4 1

Mathematics
1 answer:
iren2701 [21]2 years ago
5 0
21


hdhxhhd

s leslie correct answer
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What is the equation of the circle with center (16, - 12) and a radius of 5
eimsori [14]

Answer:

x^2+y^2-32x+24y+375=0

Step-by-step explanation:

Equation of circle with given centre (h,k) and radius=r is

(x-h)^2+(y-k)^2=r^2

Given centre are=(16, - 12) and radius= 5

So equation of circle=

(x-16)^2+(y- -12)^2=5^2

x^2-32x+256+y^2+24y+144=25

x^2+y^2-32x+24y+375=0

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ANSWER THIS CORRECTLY FOR BRAINLIEST (ALGEBRA)
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Step-by-step explanation:

I am not clear your question.

5^(-2) / ( 5^(-3) * 5^(4))

When base is equal at multifaction index should be add.

ie. (-3)  + 4 =1

5^(-2) / ( 5^((-3) +4))

5^(-2) / ( 5^(1))

When base is equal at division index should be substract.

5^(-2) / ( 5^(1))

5^((-2 )+ (-1) )

5^(-3)

We know a^(-2)= 1/ a^2

1/ 5^(3)

5 0
2 years ago
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