1) 0.1591035847
2) a to the 3rd power (3+5a)
3)3/a to the 22nd power
11760825 = 1 × 10000000 + 1×1000000+7×100000+6×10000+0+8×100+2×10+5
Answer:
479,001,600 different arrangements
Step-by-step explanation:
Answer:
Kevin needs 96 points on his last test to raise his mean test score to 90 points.
Step-by-step explanation:
we know that
The mean score is the total of all scores divided by the total number of tests.
Let
x_1 ----> the score in the first math test
x_2 ----> the score in the second math test
x_3 ----> the score in the third math test
x_4 ----> the score in the fourth math test
we have
After taking the first 3 tests, his mean test score is 88 points
so

----> equation A
How many points does he need on his last test to raise his mean test score to 90 points?
so

----> equation B
substitute equation A in equation B

solve for x_4


Therefore
Kevin needs 96 points on his last test to raise his mean test score to 90 points.
1) the standar form of the equation is ax+by = c, therefore, for y = -2/3x+5, multiply by 3 the previous equation, and its result is 3y = -2x+15⇒ 3y +2x = 15
the final result is 2x+3y = 15