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kumpel [21]
3 years ago
14

A full 355 ml can of coke is leaking at a rate of 5 ml per minute into an empty can. How long will it take for the two cans to h

ave the same amount, a, of coke?
Mathematics
2 answers:
kati45 [8]3 years ago
5 0
Thank you for posting your math question here. It take for the two cans to have the same amount, a, of coke for 35.5 minutes, assuming that the two cans has the same capacity. Below is the solution:<span>

355 - 5x = 5x => x = 35.5 minutes</span>
erastovalidia [21]3 years ago
3 0

Answer:

35.5 minutes.

Step-by-step explanation:

Let x represent time in minutes.

We have been given that a full 355 ml can of coke is leaking at a rate of 5 ml per minute into an empty can. We are asked to find the time it will take for the two cans to have the same amount, a, of coke.  

Since coke is leaking at a rate of 5 ml per minute, so in x minutes amount of coke leaked will be 5x.

We can set an equation as:

355-5x=5x

355-5x represents amount of coke left in 1st cone and 5x represents amount of coke filled in 2nd can.

Let us solve for x.

355-5x+5x=5x+5x

355=10x

10x=355

\frac{10x}{10}=\frac{355}{10}

x=35.5

Therefore, it will take 35.5 minutes for the two cans to have the same amount, a, of coke.

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The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 5 . If there were
Nitella [24]

Answer: 6456

Step-by-step explanation:

Ratio of yes to no= 7:5

Number if yes= 3766

Since total number of yes is 3766. To find the total number of votes, 3766 / (7/7+5)

= 3766/ (7/12)

= 3766 × 12/7

= 45192/7

= 6456

There were 6456 total votes

5 0
4 years ago
Scientific notation<br> 9.78 × 10^5 - 732,000<br> It has to be either 2.46 × 10^5 or 2.46 × 10^3
Morgarella [4.7K]

Answer:

2.46\times 10^5

Step-by-step explanation:

9.78 \times 10^5 - 732,000\\= 9.78 \times 10^5 - 7.32 000\times 10^5\\= 9.78 \times 10^5 - 7.32\times 10^5\\= 2.46\times 10^5

3 0
4 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
How many digits are written when 1000 to the power of 2015 is expressed as a numeral?
PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

1000^{2015}

We have to find the number of digits ,

So,

1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}

Since we know that

10^n\text{ has n+1 number of digits }

so,

10^{6045}\text{ has 6046 number of digits }

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0
3 years ago
Find value of p in..6p-1/3(p+1)=8(p+1/32​
puteri [66]

The answer is,

p =  -  \frac{1}{4}

6 0
3 years ago
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