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3 years ago

Can you Shaw me how to do 77x88 im so confused rn

Mathematics

1 answer:

Eddi Din [679]3 years ago

4 0

Answer:

6776

Step-by-step explanation:

-----

8 times 7=56 8 times 70= 560 then add together so 616 next line 80 times 7= 560 80 times 70=5600 then add those together 6160 then add the too totals together 6160+ 616= 6776

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find the maximum number of children to whom 30 sweaters and 45 trousers can be equally divided. also how many sweaters and trous

dusya [7]

Answer:

five kids .each 6 sweaters and 9 trousers

Step-by-step explanation:

4 0

3 years ago

Simplify by dividing negative three over eight divided by five over nine..

rewona [7]

Answer:

-27/40

Step-by-step explanation:

Negative twenty seven over forty

7 0

3 years ago

What's the difference between 1261⁄4 and 78 2⁄3?

lubasha [3.4K]

126 1/4 - 78 2/3 =
505/4 - 236/3 =
1515/12 - 944/12 =
571/12 =
47 7/12 <==

4 0

3 years ago

Read 2 more answers

Let $a_1$, $a_2$, . . . , $a_{10}$ be an arithmetic sequence. If $a_1 + a_3 + a_5 + a_7 + a_9 = 17$ and $a_2 + a_4 + a_6 + a_8 +

vfiekz [6]

a be first term and d be common difference

a+a+2d+a+4d+a+6d+a+9d=17
5a+21d=17--(1)

And

a+d+a+3d+a+5d+a+7d+a+9d=15
5a+25d=15--(2)

Eq(1)-Eq(2)

-4d=-2
d=1/2

Put in second one

5a+25d=15
a+5d=3
a+5/2=15
a=15-5/2
a=25/2

7 0

2 years ago

What are the first and last terms of this geometric series

11Alexandr11 [23.1K]

ANSWER

E. 10 and 640

EXPLANATION

The given series is

$\sum_{i=1}^45 \times 2^{2i-1}$

To find the first term of the series we substitute i=1 to get,

$a_1 = 5 \times {2}^{2 \times 1 - 1}$

$a_1 = 5 \times {2}^{ 1} = 10$

For the last term of the series, we substitute i=4 to obtain,

$a_4 = 5 \times {2}^{2 \times 4 - 1}$

$a_4 = 5 \times {2}^{7}$

This implies that,

$a_4 = 5 \times 128 = 640$

Therefore the correct answer is E

7 0

3 years ago