Answer:
2nd car is running faster than the first car by 2.01 units.
Step-by-step explanation:
Let's assume that
- the velocity of first car,
![v_1\ =\ 20i\ +\ 25j](https://tex.z-dn.net/?f=v_1%5C%20%3D%5C%2020i%5C%20%2B%5C%2025j)
- and the velocity of second car
![v_2\ =\ 30i](https://tex.z-dn.net/?f=v_2%5C%20%3D%5C%2030i)
=> speed of first car,
![u_1\ =\ \sqrt{(20)^2+(25)^2}](https://tex.z-dn.net/?f=u_1%5C%20%3D%5C%20%5Csqrt%7B%2820%29%5E2%2B%2825%29%5E2%7D)
![=\ \sqrt{400+625}](https://tex.z-dn.net/?f=%3D%5C%20%5Csqrt%7B400%2B625%7D)
![=\ \sqrt{1025}](https://tex.z-dn.net/?f=%3D%5C%20%5Csqrt%7B1025%7D)
= 32.01 units
and speed of second car,
![u_2\ =\ \sqrt{(30)^2+(0)^2}](https://tex.z-dn.net/?f=u_2%5C%20%3D%5C%20%5Csqrt%7B%2830%29%5E2%2B%280%29%5E2%7D)
= 30 units
![u_2\ -\ u_1\ =\ 32.01\ -30](https://tex.z-dn.net/?f=u_2%5C%20-%5C%20u_1%5C%20%3D%5C%2032.01%5C%20-30)
= 2.01 units
Hence, 2nd car is running faster than the first car by 2.01 units.
1.924 and 5.77
step 1: find the mean by adding up all the numbers and divide the sum by the number of numbers.
step 2: find the difference between each number and the mean, square the difference
step 3: add up all the results of step 2, divide the sum by (n-1), n is the number of numbers.
step 4: square root the result of step 3.
it is a long process.
4(4+2) + 5(5+3)
4x6 + 5x8
24 + 40
64 is your answer
The answer is 32
Hope this helps:D
have a great rest of a brainly day!
Answer: First, you identify how many rises and runs the line is from each point on a graph (intersection). Then you take the y's and the x's and do y2-y1/x2-x1 to get the slope!